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The length of time required to complete the test normally distributed with mean 75 minutes and standard deviation 15 minutes. achievement Sufficient time for 95% of students to complete the

The length of time required to complete the test normally distributed with mean 75 minutes and standard deviation 15 minutes. achievement Sufficient time for 95% of students to complete the

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Please show all steps. Please DO NOT skip any steps as I will not understand what you actually did. QUESTION: How did you get Z = 1.65 from 95%z. Would that not be Z = 1.960? Please show every step. This has confused me.
The length of time required to complete the achievement test normally distributed with mean 75 minutes and standard deviation 15 minutes. Sufficient time for 95% of students to complete the test. P(z)= 0.95 Where, the z value corresponds to the 0.95 is 1.65 Now, P(z)=0.95 z=1.65 -=1.65 x-75 15 Area = 0.95 u = 75 z = 1.65 x = 99.75 X= =(1.65 × 15)+75 =99.75 Thus, 99.75 minutes required by 95% of students to complete the test.
Transcribed Image Text:The length of time required to complete the achievement test normally distributed with mean 75 minutes and standard deviation 15 minutes. Sufficient time for 95% of students to complete the test. P(z)= 0.95 Where, the z value corresponds to the 0.95 is 1.65 Now, P(z)=0.95 z=1.65 -=1.65 x-75 15 Area = 0.95 u = 75 z = 1.65 x = 99.75 X= =(1.65 × 15)+75 =99.75 Thus, 99.75 minutes required by 95% of students to complete the test.
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