The molar solubility of Zn:(PO4)2 is 5.6 × 10-5 M at a certain temperature. Determine the value of Ksp for Zn3(PO4)2. PREV 1 2 Based on the set up of your ICE table, construct the expression for Ksp and then evaluate it. Do ot combine or simplify terms. Ksp

Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Mark S. Cracolice, Ed Peters
Chapter18: Chemical Equilibrium
Section: Chapter Questions
Problem 3E
icon
Related questions
icon
Concept explainers
Question
The molar solubility of Zn3(PO4)2 is 5.6 x 10-5 M at a certain temperature.
Determine the value of Ksp for Zn:(PO4)2.
1
2
NEXT
>
Based on the given values, fill in the ICE table to determine concentrations of all reactants and
products.
Zn:(PO:):(s)
3 Zn?-(aq)
2 PO. (aq)
1L
+
Initial (M)
Change (M)
Equilibrium (M)
5 RESET
5.6 x 10-5
-5.6 x 10-5
1.12 x 104
-1.12 x 104
1.68 x 104
-1.68 x 104
+x
+2x
+3x
-X
-2х
-3x
5.6 x 10-5 + x
5.6 x 10-5 - x
1.12 x 104 + 2x
1.12 x 104 - 2х
1.68 x 104 + 3x
1.68 x 10 4 - Зх
Transcribed Image Text:The molar solubility of Zn3(PO4)2 is 5.6 x 10-5 M at a certain temperature. Determine the value of Ksp for Zn:(PO4)2. 1 2 NEXT > Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. Zn:(PO:):(s) 3 Zn?-(aq) 2 PO. (aq) 1L + Initial (M) Change (M) Equilibrium (M) 5 RESET 5.6 x 10-5 -5.6 x 10-5 1.12 x 104 -1.12 x 104 1.68 x 104 -1.68 x 104 +x +2x +3x -X -2х -3x 5.6 x 10-5 + x 5.6 x 10-5 - x 1.12 x 104 + 2x 1.12 x 104 - 2х 1.68 x 104 + 3x 1.68 x 10 4 - Зх
The molar solubility of Zn:(PO4)2 is 5.6 × 10-5 M at a certain temperature.
Determine the value of Ksp for Zn:(PO4)2.
PREV
1
2
Based on the set up of your ICE table, construct the expression for Ksp and then evaluate it. Do
not combine or simplify terms.
Ksp =
%3D
5 RESET
[0]
[5.6 x 101
[1.12 x 10]
[1.68 х 10-]
[5.6 x 10-1?
[1.12 x 10-j
[1.68 x 10j
[x]
[2x]?
[3x]°
[5.6 x 105 + x]
[5.6 x 10-5 - x]
[1.12 x 104+ 2x]?
[1.12 x 104- 2x]²
[1.68 x 104 + 3x]°
[1.68 x 104- 3x]³
5.6 x 10-5
1.7 x 10-13
1.9 x 10-8
5.9 x 10-20
Transcribed Image Text:The molar solubility of Zn:(PO4)2 is 5.6 × 10-5 M at a certain temperature. Determine the value of Ksp for Zn:(PO4)2. PREV 1 2 Based on the set up of your ICE table, construct the expression for Ksp and then evaluate it. Do not combine or simplify terms. Ksp = %3D 5 RESET [0] [5.6 x 101 [1.12 x 10] [1.68 х 10-] [5.6 x 10-1? [1.12 x 10-j [1.68 x 10j [x] [2x]? [3x]° [5.6 x 105 + x] [5.6 x 10-5 - x] [1.12 x 104+ 2x]? [1.12 x 104- 2x]² [1.68 x 104 + 3x]° [1.68 x 104- 3x]³ 5.6 x 10-5 1.7 x 10-13 1.9 x 10-8 5.9 x 10-20
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Knowledge Booster
Ionic Equilibrium
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Introductory Chemistry: An Active Learning Approa…
Introductory Chemistry: An Active Learning Approa…
Chemistry
ISBN:
9781305079250
Author:
Mark S. Cracolice, Ed Peters
Publisher:
Cengage Learning
Chemistry: Matter and Change
Chemistry: Matter and Change
Chemistry
ISBN:
9780078746376
Author:
Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:
Glencoe/McGraw-Hill School Pub Co