The moment of inertia of the ball about an axis through the center of the ball isUse the parallel axis theorem to get the total moment of inertia for a pendulum of length I with a ball of radius r.Iball-a²/mL²Iball-aiIball-at-LIball-at-L= //m(r + L)²mr² +m[²//m(r² + L²)mr² L²-at-L=-at-L=Iball-at-at-L==Iball-at-L=-at-L250=//mr²{mr²75Iball-aIball-at-L = ²mrL2/52Iball = ²/mr²

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Description: The moment of inertia of the ball about an axis through the center of the ball isUse the parallel axis theorem to get the total moment of inertia for a pendulum of length I with a ball of radius r.Iball-a²/mL²Iball-aiIball-at-LIball-at-L= //m(r + L)

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The moment of inertia of the ball about an axis through the center of the ball is Iball = ²/mr² Use the parallel axis theorem to get the total moment of inertia for a pendulum of length L with a ball of radius r. Iball-at-L= ²mL² O O O O O O O O Iball-at-L= mr² mr² Iball-at- -at-L= Iball-at-L= m(r + L)² Iball-at-L= mr² + mL² Iball-at-L = m(r² + 1²) Iball-at-L= mr² L² Iball-at-L= mrL

The moment of inertia of the ball about an axis through the center of the ball is Iball = ²/mr² Use the parallel axis theorem to get the total moment of inertia for a pendulum of length L with a ball of radius r. Iball-at-L= ²mL² O O O O O O O O Iball-at-L= mr² mr² Iball-at- -at-L= Iball-at-L= m(r + L)² Iball-at-L= mr² + mL² Iball-at-L = m(r² + 1²) Iball-at-L= mr² L² Iball-at-L= mrL

Classical Dynamics of Particles and Systems

5th Edition

ISBN:9780534408961

Author:Stephen T. Thornton, Jerry B. Marion

Publisher:Stephen T. Thornton, Jerry B. Marion

Chapter8: Central-force Motion

Section: Chapter Questions

Problem 8.9P

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