The normal lens on a 35-mm camera has a focal lengthof 50.0 mm. Its aperture diameter varies from a maximumof 25 mm (f/ 2) to a minimum of 3.0 mm ( f/16). Determinethe resolution limit set by diffraction for ( f/2) and ( f/16).Specify as the number of lines per millimeter resolved onthe detector or film. Take λ=560nm

The normal lens on a 35-mm camera has a focal lengthof 50.0 mm. Its aperture diameter varies from a maximumof 25 mm (f/ 2) to a minimum of 3.0 mm ( f/16). Determinethe resolution limit set by diffraction for ( f/2) and ( f/16).Specify as the number of lines per millimeter resolved onthe detector or film. Take λ=560nm

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter4: Diffraction

Section: Chapter Questions

Problem 71P: A camera uses a lens with aperture 2.0 cm. What is the angular resolution of a photograph taken at...

See similar textbooks

Similar questions

A camera uses a lens with aperture 2.0 cm. What is the angular resolution of a photograph taken at 700 nm wavelength? Can it resolve the millimeter markings of a ruler placed 35 m away?
A good quality camera “lens” is actually a system of lenses, rather than a single lens, but a side effect is that a reflection from the surface of one lens can bounce around many times within the system, creating artifacts in the photograph. To counteract this problem, one of the lenses in such a system is coated with a thin layer of material (n=1.28) on one side. The index of refraction of the lens glass is 1.68. What is the smallest thickness of the coating that reduces the reflection at 640 nm by destructive interference? (In other words, the coating’s effect is to be optimized for =640 nm .)
If a microscope can accept light from objects at angles as large as =70 , what is the smallest structure that can be resolved when illuminated with light of wavelength 500 nm and (a) the specimen is in air? (b) When the specimen is immersed in oil, with index of refraction of 1.52?
A Michelson interferometer is used to measure the wavelength of light put through it. When the movable mirror is moved by exactly 0.100 mm, the number of fringes observed moving through is 316. What is the wavelength of the light?
On a bright clear day, you are at the top of a mountain and looking at a city 12 km away. There are two tall towers 20.0 m apart in the city. Can your eye resolve the two towers if the diameter of the pupil is 4.0 mm? If not, what should be the minimum magnification power of the telescope needed to resolve the two towers? In your calculations use 550 nm for the wavelength of the light.
Suppose a certain person’s visual acuity is such that he can see objects clearly that form an image 4.00mhigh on his retina. What is the maximum distance at which he can read the 75.0-cm-high letters on the side of an airplane?
Suppose that a correct exposure is 1/250 at f/ 11. Underthe same conditions, what exposure time would be neededfor a pinhole camera (Problem 64) if the pinhole diameter is1.0 mm and the film is 7.0 cm from the hole? 64. A pinhole camera uses a tiny pinhole instead of alens. Show, using ray diagrams, how reasonably sharpimages can be formed using such a pinhole camera. Inparticular, consider two point objects 2.0 cm apart that are1.0 m from a 1.0-mm-diameter pinhole. Show that on apiece of film 7.0 cm behind the pinhole the two objectsproduce two separate circles that do not overlap.
The normal human eye has maximum visual acuity with a pupil size of about 3 mm. For larger pupils, acuity decreases due to increasing aberrations; for smaller pupils, acuity decreases due to increasing effects of diffraction. Ifyour pupil diameter is 2.0 mm, as it would be in fairly bright light, what is the smallest diameter circle that you can barely see as a circle, rather than just a dot, if the circle is at your near point, 25 cm from your eye? Assume the light’s wavelength in air is 600 nm and the index of refraction inside theeye is 1.33.
What is the smallest possible feature size that can be resolved by using a 193-nm optical source and the highest possible NA that can be obtained by a lens when exposing the image in air? Note that NA can be determined by the equation NA = n∙sin(θ) where n is the index of refraction of the medium in which the lens is working (air in this instance) and θ is the maximal half-angle of the cone of light that can enter or exit the lens and has a maximum possible value of 90˚ for a very large lens.
The resolution of a TEM is limited by diffraction (Rd) as discussed in Chapter 1, Eq. (1.3)), and by the spherical aberration which is expressed as: Rsph =Csα3, where Cs is the spherical aberration coefficient and α is the half-angle of the cone of light entering the objective lens. The TEM resolution is the quadratic sum of the diffraction resolution and spherical aberration resolution, given by the expression: R=√(R_d^2 + R_sph^2 ) The minimum R is obtained when Rd ≅ Rsph. Estimate the optimum value of α and resolution limit of TEM at 100–200 kV. (Cs ≅ 1 mm for an electromagnetic objective lens).
A coating, 177.4 nm thick, is applied to a lens to minimize reflections. Therespective indexes of refraction of the coating and of the lens material are 1.55and 1.48. What wavelength in air is minimally reflected for normal incidence inthe smallest thickness? Draw a diagram as part of your solution.
A spy satellite orbiting at 160 km above the Earth’s surface has a lens that can resolveobjects on the ground as small as 20 cm. What is the effective diameter of the lens asdetermined by diffraction consideration alone? Assume λ = 550 nm.