The one-dimensional harmonic oscillator has a potential V(x) = ka² /2. We Henote the solutions of the associated Schrödinger equation as (x), n = ), 1, 2, .... The energy of state Pn(x) is En = hw(n + 1/2) (1.73) vhere w = Vk/m. Now consider the two-dimensional harmonic oscillator which has a po- cential

Modern Physics
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ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
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Chapter7: Tunneling Phenomena
Section: Chapter Questions
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Problem 1.14
The one-dimensional harmonic oscillator has a potential V(x) = ka² /2. We
denote the solutions of the associated Schrödinger equation as n(x), n =
0, 1, 2, ... The energy of state „(x) is
En = hw(n + 1/2)
(1.73)
where w = V
Now consider the two-dimensional harmonic oscillator which has a po-
Vk/m.
tential
k
V (2, y) = (2² + y*).
(1.74)
1. Prove that Vmn(x, y)
for the two-dimensional harmonic oscillator and find the corresponding
energy. [Hint: Group the second x-derivative term together with the
ka? /2 part of the potential, and do the same for y. Be sure fully to
exploit the fact that m and n solve the Schrödinger equation for the
one-dimensional harmonic oscillator.]
Vm(x)vn(y) solves the Schrödinger equation
2. What is the ground state energy for the two-dimensional harmonic
ocillator?
3. What is the next lowest energy after the ground state, and which com-
binations of (m, n) yield this energy?
Problem 1.15
Transcribed Image Text:Problem 1.14 The one-dimensional harmonic oscillator has a potential V(x) = ka² /2. We denote the solutions of the associated Schrödinger equation as n(x), n = 0, 1, 2, ... The energy of state „(x) is En = hw(n + 1/2) (1.73) where w = V Now consider the two-dimensional harmonic oscillator which has a po- Vk/m. tential k V (2, y) = (2² + y*). (1.74) 1. Prove that Vmn(x, y) for the two-dimensional harmonic oscillator and find the corresponding energy. [Hint: Group the second x-derivative term together with the ka? /2 part of the potential, and do the same for y. Be sure fully to exploit the fact that m and n solve the Schrödinger equation for the one-dimensional harmonic oscillator.] Vm(x)vn(y) solves the Schrödinger equation 2. What is the ground state energy for the two-dimensional harmonic ocillator? 3. What is the next lowest energy after the ground state, and which com- binations of (m, n) yield this energy? Problem 1.15
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