The pendulum swings back and forth. As the height decreases, PE is lost and KE is gained and vice versa. The sum of PE and KE remains constant. MIC Position 1 Position 2 Position 3 PE=3J KE=3J PE=0J KE=6] PE=6J KE=0J A v=0m/s Position 4 PE=6J KE=0J h= F v=0m/s h= B h=. D m C m's V= E mys Image Source: https://www.physicsclassroom.com/class/energy/Lesson-2/Analysis-of-Situations-in-Which-Mechanical-Energy As the 2.0-kg pendulum bob in the above diagram swings to and fro, its height and speed change. Answer the unknown (A to E) items above using the given hints. A: 6 J = (2 kg) (9.8 m/s²)(h) Answer: B: 3 J = (2 kg) (9.8 m/s²)(h) Answer: C: 3 J (0.5)(2 kg)(v²) = Answer: = Answer: D: 0 J (2 kg) (9.8 m/s²)(h) (0.5) (2 kg)(v²) E: 6 J = Answer: F: 6 J (2 kg) (9.8 m/s²)(h) = Answer: h= m 3 m

An Introduction to Physical Science
14th Edition
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
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Chapter4: Work And Energy
Section: Chapter Questions
Problem 15SA: A simple pendulum as shown in Fig. 4.24 oscillates back and forth. Use the letter designations in...
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The pendulum swings
back and forth. As the height decreases, PE is lost and KE is gained and vice
versa. The sum of PE and KE remains constant.
-C
Position 1
Position 2
Position 3
PE=6J
PE=3J
KE=3J
Position 4
PE=6J
KE=0J
PE=0J
KE=6]
h= D
E
KE=0J
h=_ A
h = B
m
F
h=
m
v=0m's
C TVS
mys
v=0m/s
Image Source: https://www.physicsclassroom.com/class/energy/Lesson-2/ Analysis-of-Situations-in-Which-Mechanical-Energy
fro, its
As the 2.0-kg pendulum bob in the above diagram swings to
height and speed change.
Answer the unknown (A to E) items above using the given hints.
A: 6 J = (2 kg) (9.8 m/s²)(h)
Answer:
B: 3 J (2 kg) (9.8 m/s²)(h)
=
Answer:
C: 3 J
=
- (0.5)(2 kg)(v²)
Answer:
D: 0 J (2 kg) (9.8 m/s²)(h)
=
Answer:
E: 6 J =
(0.5) (2 kg)(v²)
Answer:
F: 6 J (2 kg) (9.8 m/s²)(h)
Answer:
Transcribed Image Text:The pendulum swings back and forth. As the height decreases, PE is lost and KE is gained and vice versa. The sum of PE and KE remains constant. -C Position 1 Position 2 Position 3 PE=6J PE=3J KE=3J Position 4 PE=6J KE=0J PE=0J KE=6] h= D E KE=0J h=_ A h = B m F h= m v=0m's C TVS mys v=0m/s Image Source: https://www.physicsclassroom.com/class/energy/Lesson-2/ Analysis-of-Situations-in-Which-Mechanical-Energy fro, its As the 2.0-kg pendulum bob in the above diagram swings to height and speed change. Answer the unknown (A to E) items above using the given hints. A: 6 J = (2 kg) (9.8 m/s²)(h) Answer: B: 3 J (2 kg) (9.8 m/s²)(h) = Answer: C: 3 J = - (0.5)(2 kg)(v²) Answer: D: 0 J (2 kg) (9.8 m/s²)(h) = Answer: E: 6 J = (0.5) (2 kg)(v²) Answer: F: 6 J (2 kg) (9.8 m/s²)(h) Answer:
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