The population mean zinc mass for a certain battery brand is believed to be 3.0 g. However, a recent random sample of 61 batteries had a mean mass of 3.08 g with sample standard deviation .152 g. Does this data provide compelling evidence that the population mean zinc mass exceeds 3.0 g? (a) Define the appropriate null and alternative hypotheses. (b) Using a significance level of .01, does this data provide compelling evidence that the population mean zinc mass exceeds 3.0 g?
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- If we have a sample of size 100 from a population of rope with sample mean breaking strength of 1040 pounds with standard deviation 200 pounds and we wish to run a hypothesis test with this data to see if the population mean breaking strength exceeds 1000 pounds, what is our ALTERNATE HYPOTHESIS?Use the pulse rates in beats per minute (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than 70bpm. Use a 0.05 significance level. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=70 bpm H1: μ>70 bpm B. H0: μ>70 bpm H1: μ<70 bpm C. H0: μ=70 bpm H1: μ<70 bpm D. H0: μ=70 bpm H1: μ≠70 bpm Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. ▼ Reject Fail to reject H0. There is ▼ sufficient not sufficient evidence to conclude that the mean of the population of pulse rates for adult females is ▼ not less than greater than 70 bpm.A sample of 16 items from population 1 has a sample variance of 5.4 and a sample of 20 items from population 2 has a sample variance of 2.4. Test the following hypotheses at the 0.05 level of significance.
- Based on information from a large insurance company, 67% of all damage liability claims are made by single people under the age of 25. A random sample of 53 claims showed that 42 were made by single people under the age of 25. Does this indicate that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company? Give the test statistic and your conclusion. a) z = 1.896; reject Ho at the 5% significance level b) z = -1.896; reject Ho at the 5% significance level c) z = 1.896; fail to reject Ho at the 5% significance level d) z = -1.396; fail to reject Ho at the 5% significance level e) z = 1.396; reject Ho at the 5% significance levelRecently, a large academic medical center determined that 7 of 15 employees in a particular position were male,whereas 56% of the employees for this position in the general workforce were male. At the 0.01 level of significance, is there evidence that the proportion of males in this position at this medical center is different from what would be expected in the general workforce? What are the correct hypotheses to test to determine if the proportion is different? A. H0:π≥0.56; H1:π<0.56 B. H0:π=0.56; H1:π≠0.56 C.H0:π≤0.56; H1:π>0.56 D.H0:π≠0.56; H1:π=0.56 Part 2 Calculate the test statistic. ZSTAT=enter your response here (Type an integer or a decimal. Round to two decimal places as needed.) Part 3 What is the p-value? The p-value is..... (Type an integer or a decimal. Round to three decimal places as needed.) State conclusion of test Reject/Do not reject the null hypothesis. There is sufficient/insufficient evidence to…A veterinarian is interested in researching the proportion of men and women cat owners and believes that the proportion of men cat owners is significantly different than the proportion of women cat owners. The veterinarian decides to obtain two independent samples of men and women cat owners and finds from one sample of 80 men, 30% owned cats. In the second sample of 60 women, 55% owned cats. Test the veterinarian's belief at the α=0.05α=0.05 significance level. Preliminary: Is it safe to assume that nmen≤5%nmen≤5% of all men and nwomen≤5%nwomen≤5% of all women? Yes No Verify nˆp(1−ˆp)≥10.np^(1-p^)≥10. Round your answer to one decimal place.nmenˆp(1−ˆp)=nmenp^(1-p^)= nwomenˆp(1−ˆp)=nwomenp^(1-p^)= Test the claim: Determine the null and alternative hypotheses. H0H0: pmenpmen pwomenpwomen HaHa: pmenpmen pwomenpwomen The hypothesis test is left-tailed two-tailed right-tailed Determine the test statistic. Round to two decimal places.x=x= Find the pp-value.…
- A random sample of 144 recent donations at a certain blood bank reveals that 89 were type A blood. Does this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood? Carry out a test of the appropriate hypotheses using a significance level of 0.01. State the appropriate null and alternative hypotheses. H0: p = 0.40Ha: p < 0.40H0: p = 0.40Ha: p > 0.40 H0: p ≠ 0.40Ha: p = 0.40H0: p = 0.40Ha: p ≠ 0.40 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Reject the null hypothesis. There is sufficient evidence to conclude that the percentage of type A donations differs from 40%.Reject the null hypothesis. There is not sufficient evidence to conclude that the percentage of type A donations differs from 40%. Do not reject the null…A major credit card company is interested in the proportion of individuals who use a competitor’s credit card. Their null hypothesis is H0: p=0.65H0: p=0.65, and based on a sample they find a sample proportion of 0.70 and a pp-value of 0.053. Is there convincing statistical evidence at the 0.05 level of significance that the true proportion of individuals who use the competitor’s card is actually greater than 0.65 ? Yes, because the sample proportion 0.70 is greater than the hypothesized proportion 0.65. A Yes, because the pp-value 0.053 is greater than the significance level 0.05. B No, because the sample proportion 0.70 is greater than the hypothesized proportion 0.65. C No, since the sample proportion 0.70 is exactly 0.05 away from the hypothesized proportion 0.65. D No, because the pp-value 0.053 is greater than the significance level 0.05.The mean ± 1 SD of calcium intake (in mg) among 25 females, 12-14 years of age, below the poverty level is 6.56 ± 0.64. Similarly, the mean ± 1 SD of calcium intake among 40 females, 12-14 years of age, above the poverty level is 6.80 ± 0.76. Do we have sufficient evidence to conclude that the mean intake of calcium among females below the poverty level is significantly lower than the calcium intake of females above the poverty level? State the null and alternative hypothesis in mathematical notation Ho: Ha: What is the level of significance to be used? What is the appropriate test statistic? Why? What is the critical region? Compute for the test statistic. Show all your computations below. What is the statistical decision? What is your basis for such decision? How would you conclude your findings? Be specific.
- Suppose we take a sample of 2,500 blood donors from a population for which 50% (0.5) have type O+ blood. (a) Into what range of possible values should the sample proportion fall 95% of the time, according to the Empirical Rule? to (b) If the sample included only 625 donors instead of 2,500, would the range of possible sample proportions be wider, more narrow, or the same as with a sample of 2,500 donors? Explain your answer, and explain why it makes intuitive sense. The range would be with 625 donors compared to a sample of 2,500 donors since the standard deviation of the sampling distribution would be . This makes intuitive sense because if fewer donors are included in the sample, the proportion will be reliable as an estimate of the proportion.This chart shows the results of two random samples that measured the average number of minutes per charge for AA Lithium-ion (Li-ion) rechargeable batteries versus Nickel-Metal Hydride (NiMH) rechargeable batteries. Down below shows the hypothesis test using significance level (α) = 0.05 to determine if the true average number of minutes per charge for NiMH batteries is smaller than that for Li-ion batteries. 1. From the data given from the first graph below, what would be the correct p value? (the one tail or the two tail?) t-Test: Two-Sample Assuming Unequal Variances NiMH Li-ion Mean 89.35714 95 Variance 3.93956 59.75 Observations 14 17 Hypothesized Mean Difference 0 df 19 t Stat -2.89621 P(T<=t) one-tail 0.004628 t Critical one-tail 1.729133 P(T<=t) two-tail 0.009255 t Critical two-tail 2.093024 For the bottom graph: 1.. Find the point estimate (you can do this by subtracting Group 2…Listed below are the lead concentrations in mu g/g measured in different traditional medicines. Use a 0.10 significance level to test the claim that the mean lead concentration for all such medicines is less than 20 mu g/g. Assume that the sample is a simple random sample. 3.5 15.5 16.5 15 13 12.5 21.5 16.5 22.5 16.5 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. Upper H 0 : mu greater than20 mu g/g Upper H 1 : mu less than20 mu g/g B. Upper H 0 : mu equals20 mu g/g Upper H 1 : mu less than20 mu g/g C. Upper H 0 : mu equals20 mu g/g Upper H 1 : mu not equals20 mu g/g D. Upper H 0 : mu equals20 mu g/g Upper H 1 : mu greater than20 mu g/g