The resistance of a saturated solution of PbSO4 (very insoluble salt) at 291K is of 1.7x106 Ω, being the resistivity of pure water 7.1x105 Ωcm. 1. Determine the solubility product of PbSO4 at 291K knowing that Λmº (SO4-2)=136 Ω-1cm2mol-1 and Λmº (Pb+2)=122 Ω-1cm2mol-1 . 2. How many centimeters will the ion move Pb+2 in one second when applying a potential difference of 25V between two electrodes 1 cm apart?

The resistance of a saturated solution of PbSO4 (very insoluble salt) at 291K is of 1.7x106 Ω, being the resistivity of pure water 7.1x105 Ωcm. 1. Determine the solubility product of PbSO4 at 291K knowing that Λmº (SO4-2)=136 Ω-1cm2mol-1 and Λmº (Pb+2)=122 Ω-1cm2mol-1 . 2. How many centimeters will the ion move Pb+2 in one second when applying a potential difference of 25V between two electrodes 1 cm apart?

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter25: Voltammetry

Section: Chapter Questions

Problem 25.11QAP

See similar textbooks

Chemistry

The resistance of a saturated solution of PbSO₄ (very insoluble salt) at 291K is of 1.7x10⁶ Ω, being the resistivity of pure water 7.1x10⁵ Ωcm.

1. Determine the solubility product of PbSO₄ at 291K knowing that Λ_mº (SO₄^-2)=136 Ω^-1cm²mol^-1 and Λ_mº (Pb⁺²)=122 Ω^-1cm²mol^-1 .

2. How many centimeters will the ion move Pb⁺² in one second when applying a potential difference of 25V between two electrodes 1 cm apart?

Solution: K_so=1.41·10^-11

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

The classical dissociation constant of propionic acid, C2H5CO2H, is 1.34 x10-5 moldm-3 at 250C and the limiting molar conductivities at zero concentration of hydrogen and propionate ions are 349.8 and 35.8 ohm-1 cm2 mol-1 respectively. Calculation of the resistivity of 0.100 M solution of propionic acid.
Zinc is to be used as an internal standard for the polarographic analysis of thallium. A standard solution containing twice the concentration of zinc as Thallium has a diffusion current of 1.89 µA for Ti and 3.50 µA for Zn. A 10.0g alloy was dissolved in 500 mL, 25 mL of this solution was mixed with 25 mL of 1.0 x 10-3 M Zn 2+ solution. The diffusion currents of this final solution are 18.2µA for Tl+ and 14.5µA for Zn+. Calculate % Ti in the sample analysed
In a saturated solution of BaCO3 at 298K, [Ba2+(aq)] = 7.07 x 10-5 mol L-1; [CO32- (aq)] = 7.07 x 10-5 mol L-1. Calculate the value of Ksp at this temperature. a. 8.41 x 10−3 b. 3.54 x 10−5 c. 1.41 x 10−4 d. 5.00 x 10−9 e. 7.07 x 10−5
0.5M HA sample with 0.2 dissociation; It is placed in a conductivity cell with a length of 0.9 cm and an area of 2 cm2 and its conductivity is read as 300 mS. For this purpose;a) Equivalent conductivity of the electrolyte ?b) Boundary equivalent conductivity ?c) Decomposition constant ?
Extraction of DNA involves the use of a 1 M phosphate buffer (1-liter volume) having the hydrogen ion concentration of 6.165950019 x 10-9 M. Three pKa of phosphoric acid are available Concentrated phosphoric acid (85% w/w; Sp. Gr. = 1.70; MW = 98 g/mol) Sodium dihydrogen phosphate monohydrate (MW = 138g/mol) Sodium biphosphate heptahydrate (MW = 268g/mol) Tribasic sodium phosphate monohydrate (MW = 182 g/mol) Sodium hydroxide pellets (40 grams/mol) Question: What is the pH of the solution? (answer in two decimal places) How much of the weak acid component should be used? (Note for answer: Round to the nearest hundredth and include the unit such as "grams or milliliters"; Ex. 100.00 grams or 100.00g for weight & 100.00 milliliters or 100.00 mL for volume) Question: What is the suitable buffer component to be used? (Note for the answer: Separate the two components with “and”; Ex: Ammonia and Ammonium chloride) Question: How much of the salt component should be used?…
How long will it take to dissolve 2 mg of metal A (atomic weight 100) in a solution containing A2+ from a metal electrode with area of 1.5 cm2 at an overpotential of = 0.2 V? The exchange current density (j0) for A is 3x10-3 A/cm2, the temperature T=298 K and the symmetry factor =0.4.
Exactly 6.00 ml of acetic acid (density = 1.05 g/mL), MW =60.05) was added to a 1 –liter volumetric flask, and the flask was filled to the mark with distilled water. A portion of the resulting solution was added to a conductance cell (k = 1.25 cm-1), and the conductance was found to be 416 μS. Calculate the dissociation constant Ka of acetic acid. ΛoH+= 349.8 Scm2/mole and ΛoCH3COO- = 41 Scm2/mole
What does the selectivity coefficient tell us? Is it better to have a large or a small selectivity coefficient?
will addition of 300ml 0.005M agno3 to 200ml of 0.004M Al2(SO4)3 result in oreciptation of Ag2SO4 if Ksp of Ag2SO4 is 6.65x10^8?
) 0.025 M CH3COOH solution has a specific conductance of 2.33X10-4 Scm-1,and molar conductivity at infinite dilution is 364.13 S.Cm2.mol-1. What is itsdegree of dissociation?
Calculate the solubility of lead(II) sulfate (Ksp = 2.53x10-8) in a 0.0034 M solution of sodium sulfate. Give your answer to three sig. figs. and in exponential form (e. g. 1.23E-3).
A conductivity cell was calibrated using 0.01 M KCl (κ = 1.4087x10-3 S/cm) and the measured resistance was 688 Ω. a. Determine the cell constant (include units). b. Determine the molar conductivity, Λm for a 0.0100 M AgNO3 solution in the same cell with a resistance reading of 777Ω.