The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of J g.°C the sample and by the change in temperature. The heat capacity of a certain substance has been measured to be 4.78 are heated until the temperature of the sample has changed by 6.42 °C. Suppose 189. g of the substance Write an equation that will let you calculate the heat Q that was needed for this temperature change. Your equation should contain only symbols. Be sure you define each symbol. Your equation: Definitions of your symbols: J g. °C 0 = 4.78 = 189. g = 6.42 °C olo 0 X E A S

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Chapter6: Thermochemistry
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Problem 61E: A 5.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/C g) and a 10.00-g sample of...
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The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of
J
the sample and by the change in temperature. The heat capacity of a certain substance has been measured to be 4.78
are heated until the temperature of the sample has changed by 6.42 °C.
Suppose 189. g of the substance
g.°℃
Write an equation that will let you calculate the heat Q that was needed for this temperature change. Your equation should contain only symbols. Be sure you
define each symbol.
Your equation:
g = 1
Q
Definitions of your symbols:
J
g. °C
0 = 4.78
=
189. g
0: = 6.42 °C
X
E
A
5
Transcribed Image Text:The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of the substance by the mass of J the sample and by the change in temperature. The heat capacity of a certain substance has been measured to be 4.78 are heated until the temperature of the sample has changed by 6.42 °C. Suppose 189. g of the substance g.°℃ Write an equation that will let you calculate the heat Q that was needed for this temperature change. Your equation should contain only symbols. Be sure you define each symbol. Your equation: g = 1 Q Definitions of your symbols: J g. °C 0 = 4.78 = 189. g 0: = 6.42 °C X E A 5
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