7The KCIO3 in a 0.1862 g sample of an explosive was determined by the reaction with50.00 mL of 0.01162 M Fe²+CIO3 + 6Fe²+ +6H*→ Cl¯ + 3H₂O + 6Fe³+When the reaction was complete, the excess Fe²+ was back titrated with 13.36 mL of0.07654 MCe4+. Calculate the percentage of KCIO3 in the sample.

The balanced equation for the back titration of Fe2+(aq) with Ce4+(aq) is: Fe2+(aq) + Ce4+(aq) →…

The KCIO3 in a 0.1862 g sample of an explosive was determined by the reaction with 50.00 mL of 0.01162 M Fe²+ CIO3 +6Fe²+ +6H*→ CI + 3H₂O + 6Fe³+ When the reaction was complete, the excess Fe2+ was back titrated with 13.36 mL of 0.07654 MCe4+. Calculate the percentage of KCIO3 in the sample.

The KCIO3 in a 0.1862 g sample of an explosive was determined by the reaction with 50.00 mL of 0.01162 M Fe²+ CIO3 +6Fe²+ +6H*→ CI + 3H₂O + 6Fe³+ When the reaction was complete, the excess Fe2+ was back titrated with 13.36 mL of 0.07654 MCe4+. Calculate the percentage of KCIO3 in the sample.

Chemistry by OpenStax (2015-05-04)

1st Edition

ISBN:9781938168390

Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Chapter18: Representative Metals, Metalloids, And Nonmetals

Section: Chapter Questions

Problem 25E: A chemist dissolves a 1.497-g sample of a type of metal (an alloy of Sn, Pb, Sb, and Cu) in nitric...

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Question

7
The KCIO3 in a 0.1862 g sample of an explosive was determined by the reaction with
50.00 mL of 0.01162 M Fe²+
CIO3 + 6Fe²+ +6H*→ Cl¯ + 3H₂O + 6Fe³+
When the reaction was complete, the excess Fe²+ was back titrated with 13.36 mL of
0.07654 MCe4+. Calculate the percentage of KCIO3 in the sample.

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