1- The value of pOH of HCI solution at 25 °C if cell potential of the cell is 1.6655 vPt/ H2(g. 1.0 bar.)/ HCl(x M)// Au³+(0.01 M)/Au,is

The electrode where reduction process takes place is called cathode and where oxidation takes place…

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The value of pOH of HCI solution at 25 °C if cell potential of the cell is 1.6655 v 3+ Pt/ H2(g. 1.0 bar.)/ HCl(x M)// Au³+ (0.01 M)/Au, is

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter17: Electrochemistry

Section: Chapter Questions

Problem 103CP

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

1- The value of pOH of HCI solution at 25 °C if cell potential of the cell is 1.6655 v
Pt/ H2(g. 1.0 bar.)/ HCl(x M)// Au³+
(0.01 M)/Au,
is

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Step 1: Cathode and anode

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Step 2: Overall reaction and standard reduction potential determination

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Step 3: Value of X determination by Nernst equation

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Step 4: pOH determination

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