The vibrational energy levels for XO molecule can be described by the following formula:E(n) in Joule =1.88x10-20(n+1/2) – 2.68x10-22(n+1/2)²where n is the vibrational quantum number. What would be the equilibrium dissociation energy (De) of the XO molecule in a kJ mol-1?

Energy is given by: En=n+12ωe-n+122ωexe ...... (1) where xe is the anharmonicity…

The vibrational energy levels for XO molecule can be described by the following formula: E(n) in Joule = 1.88x10-20(n+1/2) – 2.68×10-22(n+1/2)2 where n is the vibrational quantum number. What would be the equilibrium dissociation energy (De) of the XO molecule in a kJ mol-1?

The vibrational energy levels for XO molecule can be described by the following formula: E(n) in Joule = 1.88x10-20(n+1/2) – 2.68×10-22(n+1/2)2 where n is the vibrational quantum number. What would be the equilibrium dissociation energy (De) of the XO molecule in a kJ mol-1?

Physical Chemistry

2nd Edition

ISBN:9781133958437

Author:Ball, David W. (david Warren), BAER, Tomas

Publisher:Ball, David W. (david Warren), BAER, Tomas

Chapter14: Rotational And Vibrational Spectroscopy

Section: Chapter Questions

Problem 14.46E: Determine the number of total degrees of freedom and the number of vibrational degrees of freedom...

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The vibrational energy levels for XO molecule can be described by the following formula:
E(n) in Joule =
1.88x10-20(n+1/2) – 2.68x10-22(n+1/2)²
where n is the vibrational quantum number. What would be the equilibrium dissociation energy (De) of the XO molecule in a kJ mol-1?

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