The volume of a NaNO3 solution in 1000 g water at 25 °C and 1 atm can be described using the following equation: V/ cm³ = 1102.45 + 15.5236n +1.3877 +0.2149 where ne is the number of moles of NaNO3. (a) Calculate the partial molar volumes of NaNO3 and water at 1.5 m NaNO3. (b) Calculate the density of 1.5 m NaNO3 at 25 °C and 1 atm.

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter12: Solutions
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Problem 12.51QE
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The volume of a NaNO3 solution in 1000 g water at 25 °C and 1 atm can be described using
the following equation:
V/cm² = 1102.45 + 15.5236n+1.3877 +0.2149
where ne is the number of moles of NaNO3.
(a) Calculate the partial molar volumes of NaNO3 and water at 1.5 m NaNO3.
(b) Calculate the density of 1.5 m NaNO3 at 25 °C and 1 atm.
Transcribed Image Text:The volume of a NaNO3 solution in 1000 g water at 25 °C and 1 atm can be described using the following equation: V/cm² = 1102.45 + 15.5236n+1.3877 +0.2149 where ne is the number of moles of NaNO3. (a) Calculate the partial molar volumes of NaNO3 and water at 1.5 m NaNO3. (b) Calculate the density of 1.5 m NaNO3 at 25 °C and 1 atm.
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