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- 1.Which of the following correlations about the analyses of iodine and saponificationnumbers is/are incorrect?a. Alcoholic KOH: dissolve KOH to lipid sampleb. Hanus reagent: react with saturated lipid bondc. Reflux set-up: hasten reactiond. Blank titration: determine total mol of KOH2. A triacylglycerol (Sample X) was subjected to saponification analysis. 1.1 grams of thesample was refluxed with 5% alcoholic KOH and the refluxed solution was titrated with 17.2 mLof 0.44 M HCl titrant. The blank solution was titrated with 25.6 mL of the titrant.i. What is the saponification number of the sample? ii. Which of the following could be the identity of the sample? Show solutions pls a. Tripalmitin (MW: 807.3)b. Trilaurin (MW: 639.8)c. Triolein (MW: 885:4)d. Tristearin (MW: 891.48)Chlorhexidine gluconate is available in different products in concentrations of 4% w/vand 0.12% w/v. H ow many milliliters of the more dilute product may be prepared fromeach fluidounce of the more concentrated product?The polyurethane foam used for home insulation uses methane-diphenyldiisocyanate (MDI) as monomer. The MDI is prepared by acid-catalyzed reaction of aniline with formaldehyde, followed by treatment with phosgene, COCl2. Propose mechanisms for both steps.
- When some sugars dissolve in water they spontaneously undergo changes in optical rotation called mutarrotation. The Mutarrotation of D-glucopyranose is catalyzed by acid and bases. 2-Hydroxypyridine is a more effective catalyst than phenol and pyridine for this reaction because: a.Both oxygen and N in 2-hydroxypyridine act as bases increasing the rapid interconversion of sugar b. The OH of 2-hydroxypyridine serves as the base while the current N as the acid. c. 2-hydroxypyridine acts both as a base to remove the proton from the hydroxyl group in the hemiacetal and as an acid to provide a proton to the oxygen in the hemiacetal. d.Phenol and pyridine are very expensive.Polyunsaturated fatty acids (PUFA's) in oils 0.g. sunflower oil are prone to rancidity because they contain conjugated double bond systems which are easily oxidized in the presence of light or peroxides. BHT Is used as an antioxidant in oils to prevent oxidative rancidity. How do BHT prevent oils from reacting with peroxides so that they do not become rancid? Show the mechanism.A nonapeptide released by globulins in the blood in response to a waspsting. Hydrolysis gives the following amino acids: 2 Arg, Gly, 2 Phe, 3 Pro, and Ser.Edman degradation gives phenylthiohydantoin of Arg. Cleavage with carboxypeptidase gives Arg. Partial hydrolysis gives the following di- and tripeptides: Phe-Ser, Pro-GlyPhe, Pro-Pro, Ser-Pro-Phe, Phe-Arg, and Arg-Pro. What is the amino acid sequence of this peptide?
- The rate constant for the uncatalyzed reaction of two molecules of glycine ethyl ester to form glycylglycine ethyl ester is 0.6 M- 1s - 1. In the presence of Co2 +, the rate constant is 1.5 * 106 M- 1s - 1. What rate enhancement does the catalyst provide?Calculate ΔSsys° (J/K) for the catalytic hydrogenation of acetylene to ethane: C2H2(g) + H2(g) → C2H4(g) Substance S° (J/K·mol) C2H2(g) 200.8 H2(g) 130.58 C2H4(g) 219.4A stock solution of alcohol dehydrogenase (ADH) has been diluted 1 in 10 and the absorbance reading at 280 nm of this diluted solution is 0.04. Given that the absorption coefficient for ADH at 280 nm is e mg/ml = 1.6 and that you require to do 30 assays in triplicate, each assay using 2 ug of enzyme, how many ul of the stock ADH do you need to do the experiment?
- Suppose we aempt the conversion of fumaric acid to deuterated malic acid with BD3·THF,followed by oxidation with D2O2in NaOD(aq). Show all the possible stereoisomers (as Fisherprojections) that may be formed, and draw the mechanistic pathways (showing stereochemistry)that lead to these possible productsProtein: SHAYNERSE Predict the products of the following reactions with the protein given, if there is none, write NO RXN. - Biuret reagent - KOH/Pb(CH2COO)2 - Glyoxilic Acid/Conc. H2SO - Hg/HNO3 - HNO3An unknown decapeptide was isolated and characterized. Complete hydrolysis of this peptide gave : F(2), A,G,C,K,N,T, W and V. Treatment with carboxypeptidase releases A. Reaction with Edman’s reagent gave PTH-T and a nonapeptide. The nonapeptide was treated with trypsin and gave 2 peptides: (V-C-G-A) and (N-FF-W-K). Give the sequence of amino acid in the decapeptide.