This linked dataset (https://docs.google.com/spreadsheets/d/1kIAFP-iMLwaUAEIS-4BZ1ruh0rxJ07 L4ZZaGleY2Ns/copy ) lists body masses in grams for 20 mammal species, and their corresponding base metabolic rate in Watts. Copy the data into your preferred spreadsheet program, perform a natural log transform of both the base metabolic rates and the body masses of the mammals to improve the linear relationship, and then perform a linear regression on the data using the trendline feature. Use the linear regression equation to estimate (based on these data) what the base metabolic rate of a human of 54.17 kilograms is likely to be. Some hints and suggestions: Remember that your variables have been transformed, so you will need to account for this as you find the base rate in Watts. When answering, input only digits, with no spaces, and round to two decimal places. Mammal Size (kg) Base Metabolism (Watts) 4.67 11.57 1.02 2.56 0.206 0.73 0.19 0.86 0.105 0.55 0.3 1.1 61.235 61.16 0.2615 1.2 1.039 2.93 0.061 0.42 0.2615 1.2 127.006 105.34 70 82.78 2.33 4.2 1.3 1.73 9.5 16.05 1.011 2.07 0.225 1.3 0.8 4.39 102.058 89.55

This linked dataset (https://docs.google.com/spreadsheets/d/1kIAFP-iMLwaUAEIS-4BZ1ruh0rxJ07 L4ZZaGleY2Ns/copy ) lists body masses in grams for 20 mammal species, and their corresponding base metabolic rate in Watts. Copy the data into your preferred spreadsheet program, perform a natural log transform of both the base metabolic rates and the body masses of the mammals to improve the linear relationship, and then perform a linear regression on the data using the trendline feature. Use the linear regression equation to estimate (based on these data) what the base metabolic rate of a human of 54.17 kilograms is likely to be. Some hints and suggestions: Remember that your variables have been transformed, so you will need to account for this as you find the base rate in Watts. When answering, input only digits, with no spaces, and round to two decimal places. Mammal Size (kg) Base Metabolism (Watts) 4.67 11.57 1.02 2.56 0.206 0.73 0.19 0.86 0.105 0.55 0.3 1.1 61.235 61.16 0.2615 1.2 1.039 2.93 0.061 0.42 0.2615 1.2 127.006 105.34 70 82.78 2.33 4.2 1.3 1.73 9.5 16.05 1.011 2.07 0.225 1.3 0.8 4.39 102.058 89.55

Chemical Principles in the Laboratory

11th Edition

ISBN:9781305264434

Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Chapter21: Rates Of Chemical Reactions, Ii. A Clock Reaction

Section: Chapter Questions

Problem 2ASA

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subunit G.H.I please
Choices for slope: a. -1.35 x 10^4 b. 1.35 x 10^4 c. -1.09 x 10^4 d. 1.09 x 10^4 choices for y intercept: a. -27.8 b. 27.8 c. 37.4 d. -37.4 choices for pearson: a. -0.962 b. -1000 c. -0.982 activation energy a. 9.06 x 10^4 b. 113 c. 90.65 collision frequency factor A a. 1.15 x 10^12 b. 113 c. 90.65
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A protein has a stability ranging from 6 to 15 kcal/mole at 37 OC. Stability is a measure of the equilibrium between the folded and unfolded protein given by the relationship; folded(F) = unfolded (U), k=[U]/[F] For a protein with a stability of 10 kcal/mole, calculate the fraction of unfolded protein that would exist at equilibrium at 37 OC. Use the following equation: ∆GO=RTlnk=-2.3RTlog k, where R=1.98 x 10-3kcal/mole and T is temperature in Kelvin (K) and k is the equilibrium constant.
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