Three capacitors with capacitances 4 µF, 8 μF, and 12 µF are connected in series. A voltage of 400 V is applied to the combination. (a) Find the charge in each capacitor. (b) What is the voltage across each capacitor? Answers: sans edi to consizib edi gniesomsh a. QT=Q4=Q8=Q8=Q12=854.5 x 10-6 C = 8.545 × 10-4 C s gribbs yd (3) bas potiononost baasi aidh nl sottosto b. V₁=218 V litw ow V₂ = 109 V V₁2 = 72.72 V 12 innan? p ni bevet2 vers

Three capacitors with capacitances 4 µF, 8 μF, and 12 µF are connected in series. A voltage of 400 V is applied to the combination. (a) Find the charge in each capacitor. (b) What is the voltage across each capacitor? Answers: sans edi to consizib edi gniesomsh a. QT=Q4=Q8=Q8=Q12=854.5 x 10-6 C = 8.545 × 10-4 C s gribbs yd (3) bas potiononost baasi aidh nl sottosto b. V₁=218 V litw ow V₂ = 109 V V₁2 = 72.72 V 12 innan? p ni bevet2 vers

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter8: Capacitance

Section: Chapter Questions

Problem 72AP: Three capacitors having capacitances 8.4, 8.4, and 4.2 F are connected in series across a 36.0-V...

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