Tin(IV) sulfide, SnS₂, a yellow pigment, can be produced using the following reaction. SnBr4(aq) + 2 Na₂S(aq) 4 NaBr(aq) + SnS₂ (s) Suppose a student adds 44.1 mL of a 0.549 M solution of SnBr4 to 43.2 mL of a 0.132 M solution of Na₂S. Identify the limiting reactant. NaBr SnBr SnS₂ Na₂S Calculate the theoretical yield of SnS₂. theoretical yield: g

Chemistry: The Molecular Science
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Author:John W. Moore, Conrad L. Stanitski
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Chapter3: Chemical Reactions
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Tin(IV) sulfide, SnS₂, a yellow pigment, can be produced using the following reaction.
SnBr(aq) + 2 Na₂S(aq) →→→ 4 NaBr(aq) + SnS₂ (s)
Suppose a student adds 44.1 mL of a 0.549 M solution of SnBr4 to 43.2 mL of a 0.132 M solution of Na, S.
Identify the limiting reactant.
NaBr
SnBr₁ 4
SnS₂
Na₂S
Calculate the theoretical yield of SnS₂.
theoretical yield:
The student recovers 0.329 g of SnS₂. Calculate the percent yield of SnS₂ that the student obtained.
percent yield:
6.0
g
%
Transcribed Image Text:Tin(IV) sulfide, SnS₂, a yellow pigment, can be produced using the following reaction. SnBr(aq) + 2 Na₂S(aq) →→→ 4 NaBr(aq) + SnS₂ (s) Suppose a student adds 44.1 mL of a 0.549 M solution of SnBr4 to 43.2 mL of a 0.132 M solution of Na, S. Identify the limiting reactant. NaBr SnBr₁ 4 SnS₂ Na₂S Calculate the theoretical yield of SnS₂. theoretical yield: The student recovers 0.329 g of SnS₂. Calculate the percent yield of SnS₂ that the student obtained. percent yield: 6.0 g %
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