Tn Course: 2020SP General Chemist X W Homework #13: Hess's Law CH X A webassign.net/web/Student/Assignment-Responses/last?dep=23543846 Apps Bookmarks Th Robeson Communi... R Robeson Communi... O VitalSource Booksh... G Google 2. -/1 POINTS OSGENCHEM1 5.3.P.063. MY N Calculate AH98 (in kJ) for the process P(s) + 5/2 Cl, (g) → PCI-(g) from the following information. 5. P(s) + 3/2 Cl,(g) → PCI,(g) PCI,(g) + Cl,(g) – PCI,(g) дн298 AH298 = -287 kJ = -88 kJ 4.0 Supporting Materials Periodic Table Constants and Supplemental Data Factors Additional Materials Section 5.3 3. -/1 POINTS OSGENCHEM1 5.3.P.066. MY NO Calculate AH298 (in kJ) for the process Co,0(s) 3 Co(s) + 2 0,(g) from the following information. Co(s) + 1/2 0,(g) - Co0(s) дн298 = -237.9 k 3 Coo(s) + 1/2 O,(g) - Co,0 (s) AH298 = -177.3 k] %3D 4.0 kJ WE

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Chapter6: The States Of Matter
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Tn Course: 2020SP General Chemist X
W Homework #13: Hess's Law CH X
A webassign.net/web/Student/Assignment-Responses/last?dep=23543846
Apps Bookmarks
Th Robeson Communi... R Robeson Communi...
O VitalSource Booksh...
G Google
2.
-/1 POINTS
OSGENCHEM1 5.3.P.063.
MY N
Calculate AH98 (in kJ) for the process P(s) + 5/2 Cl, (g) → PCI-(g) from the following information.
5.
P(s) + 3/2 Cl,(g) → PCI,(g)
PCI,(g) + Cl,(g) – PCI,(g)
дн298
AH298 = -287 kJ
= -88 kJ
4.0
Supporting Materials
Periodic Table
Constants and
Supplemental Data
Factors
Additional Materials
Section 5.3
3.
-/1 POINTS
OSGENCHEM1 5.3.P.066.
MY NO
Calculate AH298 (in kJ) for the process Co,0(s) 3 Co(s) + 2 0,(g) from the following information.
Co(s) + 1/2 0,(g) - Co0(s)
дн298
= -237.9 k
3 Coo(s) + 1/2 O,(g) - Co,0 (s)
AH298
= -177.3 k]
%3D
4.0
kJ
WE
Transcribed Image Text:Tn Course: 2020SP General Chemist X W Homework #13: Hess's Law CH X A webassign.net/web/Student/Assignment-Responses/last?dep=23543846 Apps Bookmarks Th Robeson Communi... R Robeson Communi... O VitalSource Booksh... G Google 2. -/1 POINTS OSGENCHEM1 5.3.P.063. MY N Calculate AH98 (in kJ) for the process P(s) + 5/2 Cl, (g) → PCI-(g) from the following information. 5. P(s) + 3/2 Cl,(g) → PCI,(g) PCI,(g) + Cl,(g) – PCI,(g) дн298 AH298 = -287 kJ = -88 kJ 4.0 Supporting Materials Periodic Table Constants and Supplemental Data Factors Additional Materials Section 5.3 3. -/1 POINTS OSGENCHEM1 5.3.P.066. MY NO Calculate AH298 (in kJ) for the process Co,0(s) 3 Co(s) + 2 0,(g) from the following information. Co(s) + 1/2 0,(g) - Co0(s) дн298 = -237.9 k 3 Coo(s) + 1/2 O,(g) - Co,0 (s) AH298 = -177.3 k] %3D 4.0 kJ WE
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