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To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 33 31 21 23 32 26 35 35 26 38 24 28 31 28 29

To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 33 31 21 23 32 26 35 35 26 38 24 28 31 28 29

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter11: Data Analysis And Displays
Section11.4: Two-ways Tables
Problem 12E
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How do i find the test statistic? I need help seeing the step by step or doing it in excel if that is where I do it!

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Hint(s) Check My Work To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 33 31 21 23 32 26 35 35 26 38 24 28 31 28 29 Construct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square p-value Treatments 93.33 2 46.67 2.37 .1354 Error 236 12 19.67 Total 329.33 14 Use a 0.05 level of significance to test whether the temperature level has an effect on the mean yield of the process. Calculate the value of the test statistic (to 2 decimals). 3.89 The p-value is greater than 0.10 What is your conclusion? Do not reject the assumption that the mean yields for the three temperatures are equal
Transcribed Image Text:Hint(s) Check My Work To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. Temperature 50°C 60°C 70°C 33 31 21 23 32 26 35 35 26 38 24 28 31 28 29 Construct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square p-value Treatments 93.33 2 46.67 2.37 .1354 Error 236 12 19.67 Total 329.33 14 Use a 0.05 level of significance to test whether the temperature level has an effect on the mean yield of the process. Calculate the value of the test statistic (to 2 decimals). 3.89 The p-value is greater than 0.10 What is your conclusion? Do not reject the assumption that the mean yields for the three temperatures are equal
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