Solve this Carefully, Write clearly and Circle the Final answer for Tmax with the correct units and for Part B T = with the right units To use the torsion formula to relate the torque applied to a rod of circular cross section to themaximum shear stress in the rod.• Part A- Maximum stressWhen a torque T is applied to a shaft with a circular cross section, the shaft will deform by twistingabout its longitudinal axis. For small deflections, the radial lines will remain straight and the crosssections will remain planar and parallel. The shear strain within the shaft will vary linearly along anyradial line (Eigure 1)A cross section of a solid circular rod is subject to a torque of T- 23 kN m. If the diameter of the rod is D-8 cm, what is the maximum shear stress?Express your answer with appropriate units to three significant figures.If the material is homogenous and elastic, then the shear stress will also vary linearly along any radialine as long as the maximum shear stress is no greater than the proportional limit for the materialSince the shear stress varies linearly, the maximum will occur on the outer boundary of the cross> View Available Hint(s)section.ТрThe shear stress T at a point on the cross section is related to the torque at the section by T=where p is the distance of the point from the central axis and J is called the polar moment of inertiaof the cross-sectional area. For a solid circular shaft J = c, where c is the shaft radius. For aTmaxValueUnitscircular tube with inner radius c, and outer radius Co. the polar moment of inertia isJ =SubmitPart B- TorqueThe maximum stress in a section of a circular tube subject to a torque is T 37 MPa. If the inner diameter is D; -5 cm and the outer diameter is D. -7 cm, what is the torque on the section?Express your answer with appropriate units to three significant figures.• View Available Hint(s)a1 ?T- ValueUnitsSubmitProvide FeedbackNext >FigureO 1 of 1 >T

Answered: Image /qna-images/answer/89676ad1-91b3-47bb-8489-a04faf2319e9.jpg

To use the torsion formula to relate the torque applied to a rod of circular cross section to the maximum shear stress in the rod. Part A- Maximum stress When a torque T is applied to a shaft with a circular cross section, the shaft will deform by twisting about its longitudinal axis. For small deflections, the radial lines will remain straight and the oross sections will remain planar and paralel. The shear strain within the shaft will vary linearly along any radial ine (Eigure 1) A cross section of a solid circular rod is subject to a torque of T- 23 kN m. If the diameter of the rod is D8 cm , what is the maximum shear stress? Express your answer with appropriate units to three significant figures. If the material is homogenous and elastic, then the shear stress will also vary linearly along any radal Ine as long as the maximum shear stress is no greater than the proportional imit for the material Since the shear stress varies inearly, the maximum will occur on the outer boundary of the cross section > View Available Hint(s) The shear stress r at a point on the cross section is related to the torque at the section by T=. where p is the distance of the point from the central axis and J is called the polar moment of inertia of the cross-sectional area. For a solid circular shaft J=e, where e is the shaft radius. For a circular tube with inner radius e and outer radius Ce, the polar moment of inertia is J-(-e). Value Units Submit • Part B- Torque The maximum stress in a section of a circular tube subject to a torque is T 37 MPa. If the inner diameter is D, -5 cm and the outer diameter is D.7 cm, what is the torque on the section? Express your answer with appropriate units to three significant figures. View Available Hint(s) O DI ? T- Value Units Submit Provide Feedback Next

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter3: Torsion

Section: Chapter Questions

Problem 3.3.11P: A circular tube of aluminum is subjected to torsion by torques T applied at the ends (see figure)....