Question
Asked Dec 15, 2019
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Would this be an SN1 or SN2 reaction? And why?

To1519
MRAN
+Na
CH3
t NaBr
CH3Br
(2]CH3 Br
0-CH3
Ba
in
t NaBr
CH3B
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To1519 MRAN +Na CH3 t NaBr CH3Br (2]CH3 Br 0-CH3 Ba in t NaBr CH3B

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Expert Answer

Step 1

Cyclohexanone reacts in the presence of sodium hydride to form an enolate anion and the removal of hydrogen gas occurs side by side. The enolate anion which further reacts with alkyl halide to form an alkylated product.

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:: и Na H Nat -H2 И :0: :0: CHs (5) Nat Си, Ви + Na By (T) Na BM

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Step 2

Sodium hydride present in the reaction protonates the oxo group of cyclohexanone and the adjacent carbon atom which leads to the formation of a nucleophilic enolate ani...

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