TRIAL 1 TRIAL 2 TRIAL 3 Mass of Vitamin C (mg) 11 mg 12mg 11mg Initial buret reading of lodine titrant, ml 100 mL 100 mL 100 mL Final buret reading of lodine titrant, mL 41.7 ml 38.2 mL 43.89 ml Volume of lodine solution used, ml 58.3 ml 61.8 mL 56.1 ml Mass Vitamin C, mg Volume of lodine solution used, mL 0.19 mg ml 0.19 mg ml 0.20 mg ml Average mass of Vitamin C, mg/ volume of lodine solution used, mL 0.19 mg/ml 0.19 mg/mL 0.19 mg/mL Molarity l, Average Molarity l2

TRIAL 1 TRIAL 2 TRIAL 3 Mass of Vitamin C (mg) 11 mg 12mg 11mg Initial buret reading of lodine titrant, ml 100 mL 100 mL 100 mL Final buret reading of lodine titrant, mL 41.7 ml 38.2 mL 43.89 ml Volume of lodine solution used, ml 58.3 ml 61.8 mL 56.1 ml Mass Vitamin C, mg Volume of lodine solution used, mL 0.19 mg ml 0.19 mg ml 0.20 mg ml Average mass of Vitamin C, mg/ volume of lodine solution used, mL 0.19 mg/ml 0.19 mg/mL 0.19 mg/mL Molarity l, Average Molarity l2

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.25QAP

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(a) During the analysis of water sample by argentometric titration, results obtained are as follows: Experiment1 2 3 4 Volume 15.5, 15.2 ,15.1 ,15.4 A)Calculate average deviation and relative average deviation for the given data. (b)Calculate the molecular weight of an unknown acid if 8.5 g of it is dissolved in 200.0 ml of water and requires 50.0 ml of 1.5 M sodium hydroxide for complete neutralization .
An EDTA solution was prepared by dissolving the disodium salt in 1 L of water. It was standardized using 0.5063 gram of primary standard calcium carbonate (MM: 100.08) and consumed 28.50 mL of the solution. The standard solution was used to determine the hardness of a 2 L sample of mineral water, which required 35.57 mL of EDTA solution. 1. What is the analyte in the analysis? Answer 2. What is concentration (M) of the EDTA solution used in the analysis? Answer 3. What is the concentration (ppm) of CaCO3 in the sample?
Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?
Answer the following: Maria was given a capsule of multivitamins and she was asked to determine the % by mass (w/w) of ascorbic acid present in the sample. The student analyzed 1.032 g sample using volumetric titration. Use the table as a reference of the data to be used for your solution. Given Choices: A. 66.0 % B. 54.6% C. 65.6% D. 7.30%
An unknown sample of Cu2+gave an absorbance of 0.262. Then 1.00 mL of solution containing 100 ppm (ug/mL)Cu2+was mixed with 95.0 mL of the unknown and the mixture was diluted to 100 mL in a volumetric flask with deionized water. The absorbanceof the new solution was 0.500. a.Denoting the initial unknown concentrationas [Cu2+]i,write an expression for the final concentrationafter dilution [Cu2+] b.Find [Cu2+]in the unknown.
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1) Titrant 5 mg H2O/ mL Resolution 2.5 µg H2O/step Detection limit is 125 µg H2O for a 5 g sample (= 25 ppm) 2) Titrant 2 mg H2O/ mL Resolution 1 µg H2O/step Detection limit is 50 µg H2O for a 5 g sample (= 10 ppm) You have a 10 g sample which is expected to contain 200 µg H2O. True or false? 1. Titrant 5mg/mL is the preferred system over 2. Titrant 2mg/mL for this sample. True False
How much calcium would you ingest by drinking one 8 oz glass of your tap water? Show all calculations. Tap Water Trial 1 Tap Water Trial 2 Tap Water Trial 3 Initial Syringe Reading 1.0ml 1.0ml 1.0ml Final Syringe Reading 0.65ml 0.68ml 0.67ml Volume of EDTA Consumed 0.35ml 0.32ml 0.33ml Water Hardness ppm CaCO3 70.07 ppmCaCO3 64.064 ppmCaCO3 66.066 ppmCaCO3 Average ppm 66.73 ppmCaCO3
step 1: Prepare a 1:15 soy flour-water mixture by adding l g soy flour to 15 ml distilled water in a 50-ml Falcon tube and vortex it to form a uniform suspension; pH 3.5 4.5 5.5 6.5 7.5 8.5 Dilution Factor 5 5 5 50 50 50 Absorbance 0.098 0.027 0.068 0.028 0.032 0.054 Concentration in diluted supernatant (mg/ml) 0.196 0.054 0.136 0.0056 0.0064 0.0108 Concentration in undiluted supernatant (mg/ml) 0.98 0.27 0.68 0.28 0.32 0.54 Calculate the amount (in grams) of soluble protein in the soy flour extract **Make sure to account for the dilution you made in Step 1 (Assume the volume of acid or base used to adjust the pH is negligible). Soluble protein (g) = (C x V x F) / 1000 C = concentration (mg/ml); F = dilution factor; V = volume of solution (ml)
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Trial 1 Trial 2 Initial Buret Reading 0.05 mL 0.02 mL Final Buret Reading 25.25 mL 23.22 mL Volume of base used Molarity of base used 0.1045 M 0.1045 M Volume of vinegar used 5.00 mL 5.00 mL
SELECT correct responses only 1) Volume percent (v/v%) is temperature-independent. 2) There are three major approaches to expressing solution concentration in terms of percent concentration: weight percent, volume percent, and weight/volume percent. 3) Weight/volume percent (w/v%) is a unit-less quantity. 4) The term 'percent' refers to 'parts per thousand'. 5)A standard solution is a reagent of known concentration that is used to carry out a volumetric titration. 6) The endpoint of a titration is the theoretical point reached when the amount of added titrant is chemically equivalent to the amount of analyte in a sample. 7) A substance that changes color in response to chemical equivalence is known as an indicator. 8) Given a sufficiently diligent and experienced experimenter, it is sometimes possible to reach a titration volume error value of 0.