Two manned satellites approaching one another at a relative speed of 0.100 m/s intend to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. If the two satellites collide elastically rather than dock, what is their final relative velocity? Adopt the reference frame in which the second satellite is initially at rest and assume that the positive direction is directed from the second satellite towards the first satellite. _________ m/s

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Asked Nov 29, 2019
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Two manned satellites approaching one another at a relative speed of 0.100 m/s intend to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. If the two satellites collide elastically rather than dock, what is their final relative velocity? Adopt the reference frame in which the second satellite is initially at rest and assume that the positive direction is directed from the second satellite towards the first satellite.
 _________ m/s

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Expert Answer

Step 1

According to momentum conservation law, sum of initial velocities of satellite before collision will be equal to final velocity of system after collision. In...

mu,4m = (m, + m, )v
(5.00x10 kg)(Om/s)+(7.50x10 kg) (0.100m/s) =(5.00 x 10'kg+7.50x10 kg)v
0.75x10 kg m/s
12.5x10 kg
0.06 m/s
1=
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mu,4m = (m, + m, )v (5.00x10 kg)(Om/s)+(7.50x10 kg) (0.100m/s) =(5.00 x 10'kg+7.50x10 kg)v 0.75x10 kg m/s 12.5x10 kg 0.06 m/s 1=

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