Two spheres of equal diameter have a positive 20 µC and a negative 15 µC, respectively. If they are placed 10 cm apart, what would be the force of attraction between them? is at first raised?Why is the final answer is + 270 N if one of the given values is q2= - 15 C? Find:The force of attraction between the charges: FSolution:The force of attraction between the charges is:Fd?(9x10° N - m²/c² )|20 µC||-15 µC|(10 cm)(9×10° N ·m²/C² )(20 ×10° c)(15×10 C)(0.10 m )*F = 270 NThus, the force of attraction between the charges is 270 N.

Given :- To find force of attraction between two charged spheres.

Answered: Two spheres of equal diameter have a…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter30: Atomic Physics

Section: Chapter Questions

Problem 2PE: (a) Calculate the mass of a proton using the charge-to-mass ratio given for it in this chapter and...

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Two spheres of equal diameter have a positive 20 µC and a negative 15 µC, respectively. If they are placed 10 cm apart, what would be the force of attraction between them? is at first raised?

Why is the final answer is + 270 N if one of the given values is q2= - 15 C?

Find:
The force of attraction between the charges: F
Solution:
The force of attraction between the charges is:
F
d?
(9x10° N - m²/c² )|20 µC||-15 µC|
(10 cm)
(9×10° N ·m²/C² )(20 ×10° c)(15×10 C)
(0.10 m )*
F = 270 N
Thus, the force of attraction between the charges is 270 N.

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