UESTION 2 Which answer correctly predicts the multiplicity (the number of peaks as a result of splitting) for each shaded proton in the (Assume the sample contains a trace of an acidic or basic impurity and is not ultrapure) HgC-C-OH Ha = 4, Hb = 1, Hc = 2 0 Ha 8, Hb = 2, Hc = 2 Ha 7, Hb = 1, Hc = 2 Ha = 5, Hb = 2, Hc = 2
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- Demonstrate that step 8 of the example in basic solution is balanced with respect to both mass and charge. That is, for mass balance, show that the number of each type of atom is the same on the reactant and product side, and for charge balance, show that the total charge of all species is the same on the reactant and product side.Trial 1: Initial pH= 3.92mL Mass of KHP and Paper= 0.868g Mass of paper= 0.357g Mass of KHP= 0.511g Trial 2: Initial pH= 4.09ml Mass of KHP and Paper= 0.870g Mass of paper= 0.359g Mass of KHP= 0.511g 1) find Ka and use the value of Ka to calculate the initial pH of each trial 2) calculate Kb for the C8H4O4^-2 anion from the value of Ka that you obtained for KHP.Don't give handwritten answers please ?? ot
- (9.29 × 105/8)-20.81 = with correct sig figsAcetic acid (CH3COOH, abbrev. HA) is a very common weak acid with pKA = 4.75 (at 25oC and low ionic strength). Calculate pH of the diluted solution of acetic acid with concentration c = 0.05 mol dm-3.Exactly 6.00 ml of acetic acid (density = 1.05 g/mL), MW =60.05) was added to a 1 –liter volumetric flask, and the flask was filled to the mark with distilled water. A portion of the resulting solution was added to a conductance cell (k = 1.25 cm-1), and the conductance was found to be 416 μS. Calculate the dissociation constant Ka of acetic acid. ΛoH+= 349.8 Scm2/mole and ΛoCH3COO- = 41 Scm2/mole