I need A & also the 90 interval Thankyou Use the geyser eruption duration times (in seconds) and the accompanying 200 bootstrap samples to complete parts (a) through (c) below.226 206 257 240 249 240 243 245 208 252 245 248 250 238 248 DE Click the icon to view the table of bootstrap samples.- XBootstrap samplesa. Use the bootstrap method with 200 samples to find a 95% confidence interval estimate of u.sec

Answered: Image /qna-images/answer/2b9a7023-420b-4684-a832-e02d13dc5ffc.jpg

Answered: Use the geyser eruption duration times…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Each year, Lord & Taylor, Ltd., sets up a gift-wrapping station to assist its customers with holiday shopping. Preliminary observations of one worker at the station producedthe following sample time (in minutes per package): 3.5, 3.2, 4.1,3.6, 3.9. Based on this small sample, what number of observationswould be necessary to determine the true cycle time with a 95%confidence level and an accuracy of {5%?
On the basis of the results to part A in the picture, does the manager have a right to complain to the manufacturer? does a 1 gallon paint can containing exactly 1 gallon of paint lie within the 95% confidence interval?
A U.S. Food Survey showed that Americans routinely eat beef in their diet. Suppose that in a study of 49 consumers in Illinois and 64 consumers in Texas the following results were obtained from two samples regarding average yearly beef consumption: Illinois Texas = 49 = 64 = 54.1lb = 60.4lb S1 = 7.0 S2 = 8.0 Develop a 95% confidence Interval Estimate for the difference between the two population means.
Refer to Exercise 18 in Section 9.1. a) Use the Fisher LSD method to find a 95% confidence interval for the difference between the means for annularly threaded and smooth shank nails. b) Use the Tukey–Kramer method to determine which pairs of nail types, if any, differ at the 5% level.
Suppose that 5000 students who have taken the SAT exam once are randomly assigned to either take an SAT coaching course or not, with the following results in their improvements in SAT scores when they take the exam a second time: Coaching Group Control Group Sample Sample Size Sample Mean Standard Deviation 2500 2500 46.2 44.4 12.3 5.5 Create and interpret a 90% confidence interval for the parameter of interest.
From a simple random sample of 400 of the 1,395 colleges in our population, it was found that business statistics was a two-semester course in 141 of the sampled colleges. Estimate the proportion of all colleges for which the course is two semesters long, and find a 90% confidence interval.
In an experiment of normal body temperatures in degrees Fahrenheit, 6 males ages 25-40 were given a random temperature check. The results were as follows: 97.1 99.0 98.2 98.9 98.1 99.4 a. Construct and interpret a 95% Confidence Interval for the average normal body temperature of males ages 25-40. b. Construct and interpret a 95% Prediction Interval for the next temperature taken. c. The average normal body temperature is generally accepted as 98.6 °F. Given the above data, should scientists reconsider this general statement? Use ? = 0.05.
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and the United Kingdom. They found that a substantially greater percentage of U.K. ads use humor.a. Suppose that a random sample of 400 television ads in the United Kingdom reveals that 142 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.K. television ads that use humor.b. Suppose a random sample of 500 television ads in the United States reveals that 122 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.S. television ads that use humor.c. Do the confidence intervals you computed in parts a and b suggest that a greater percentage of U.K. ads use humor? Explain.
Consider the following results for independent samples taken from two populations. Sample 1 Sample 2 n1 = 400 n2= 200 p1= 0.46 p2= 0.34 a. What is the point estimate of the difference between the two population proportions (to 2 decimals)? b. Develop a 90% confidence interval for the difference between the two population proportions (to 4 decimals). Use z-table. to c. Develop a 95% confidence interval for the difference between the two population proportions (to 4 decimals). Use z-table. to
A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain areawho favor moving the broadcast of the late weeknight news to an hour earlier than it is currently. Initially, theconfidence interval will be created using a simple random sample of 9,000 viewers in the area. Assuming that thesample proportion does not change, what would be the relationship between the width of the original confidenceinterval and the width of a second 90 percent confidence interval that is created based on a sample of only 1,000viewers in the area?(A) The second confidence interval would be 9 times as wide as the original confidence interval.(B) The second confidence interval would be 3 times as wide as the original confidence interval.(C) The width of the second confidence interval would be equal to the width of the original confidence interval.(D) The second confidence interval would be 1/3 as wide as the original confidence interval.(E) The second…
In exploring possible sites for a convenience store in a large neighbourhood, the retail chain wants to know the proportion of ratepayers in favour of the proposal. If the estimate is required to be within 0.1 of the true proportion, would a random sample of size n = 100 from the council records be sufficient for a 95% confidence interval of this precision?
Estimate the minimum sample size needed to achieve the margin of error E=0.013 for a 95% confidence interval.

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