Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a = 5m, b = 3 m, PB = 55 kN, Pc = 75 kN, and PE = 25 kN. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. a a PB Answer: Ay = i B PB a B Pc a q Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) D Pc D a Dy a PE kN, Dy= PE E i E kN.

International Edition---engineering Mechanics: Statics, 4th Edition
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Author:Andrew Pytel And Jaan Kiusalaas
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Chapter6: Beams And Cables
Section: Chapter Questions
Problem 6.42P: For the beam AB shown in Cases 1 and 2, derive and plot expressions for the shear force and bending...
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Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a = 5 m, b = 3 m, PB
= 55 kN, Pc = 75 kN, and PE = 25 kN. Construct the shear-force and bending-moment diagrams on paper and use the results to
answer the questions in the subsequent parts of this GO exercise.
a
PB
Answer: Ay = i
BO
PB
a
B
Pc
a
Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the
red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)
D
Pc
D
a
D₂
PE
a
PE
E
kN, Dy= i
-x
E
X
kN.
Transcribed Image Text:Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a = 5 m, b = 3 m, PB = 55 kN, Pc = 75 kN, and PE = 25 kN. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. a PB Answer: Ay = i BO PB a B Pc a Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) D Pc D a D₂ PE a PE E kN, Dy= i -x E X kN.
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