Use the van der Waals equation of state to determine the density of propane (C,Hg) at 400 K and 12.75 MPa. How does this value compare with that obtained from the NIST online database?

Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.49E
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a = 9.385

b = 0.090400

Use the van der Waals equation of state to
determine the density of propane (C,Hg) at 400 K
and 12.75 MPa. How does this value compare with
that obtained from the NIST online database?
Transcribed Image Text:Use the van der Waals equation of state to determine the density of propane (C,Hg) at 400 K and 12.75 MPa. How does this value compare with that obtained from the NIST online database?
Expert Solution
Step 1

Given:

Pressure = 12.75 MPa = 125.83 atm

Temperature = 400 K

a = 9.385

b = 0.090400

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