Solve the following Using the following heat of combustionsCH;OH(1) + {O;(g) → CO-(g) + 2H,0(1)A,H° = -726.4 kJ mol¬1%3DC(graphite) + O,(g) → CO-(g)AH° = -393.5 kJ mol-!H,(g) + !0,(g) → H,0(1)AH° = -285.8 kJ mol¬%3DCalculate the enthalpy of formation of ethanol (in kJ/mol; 4significant figures)C(graphite) + 2H2(g) + }0,(g) → CH;OH(1)

Answered: Image /qna-images/answer/7660a650-7677-4c60-b04f-b99740237618.jpg

Using the following heat of combustions CH;OH(1) + {O,(g) → CO,(g) + 2H,0(1) A,H° = -726.4 kJ mol-1 %3D C(graphite) + O,(g) → CO.(g) A,H° = -393.5 kJ mol-1 %3D H,(g) + !O,(g) → H,0(1) AH° = -285.8 kJ mol-! Calculate the enthalpy of formation of ethanol (in kJ/mol; 4 significant figures) C(graphite) + 2H2(g) + }O,(g) → CH;OH(1)

Using the following heat of combustions CH;OH(1) + {O,(g) → CO,(g) + 2H,0(1) A,H° = -726.4 kJ mol-1 %3D C(graphite) + O,(g) → CO.(g) A,H° = -393.5 kJ mol-1 %3D H,(g) + !O,(g) → H,0(1) AH° = -285.8 kJ mol-! Calculate the enthalpy of formation of ethanol (in kJ/mol; 4 significant figures) C(graphite) + 2H2(g) + }O,(g) → CH;OH(1)

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter4: Energy And Chemical Reactions

Section: Chapter Questions

Problem 96QRT

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