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Using this percent change data, determine the concentration of sucrose that would be isotonic.  it  does not have to be exact  Write your answer with 1 digit past the decimal point - e.g. 8.6 (a trailing zero is considered a digit)     Isotonic concentration =    Moles   0.0 M sucrose -0.24×100÷4.6= -5.2% 0.4 M sucrose = 0.39×100/4.2=9.3% 0.6 M sucrose = 0.7×100÷4=17.5%  0.8 M sucrose =0.8×100/3.7=21.6% 1.0 M sucrose =0.4×100/4.6=8.7%

Using this percent change data, determine the concentration of sucrose that would be isotonic.  it  does not have to be exact  Write your answer with 1 digit past the decimal point - e.g. 8.6 (a trailing zero is considered a digit)     Isotonic concentration =    Moles   0.0 M sucrose -0.24×100÷4.6= -5.2% 0.4 M sucrose = 0.39×100/4.2=9.3% 0.6 M sucrose = 0.7×100÷4=17.5%  0.8 M sucrose =0.8×100/3.7=21.6% 1.0 M sucrose =0.4×100/4.6=8.7%

Introductory Chemistry: An Active Learning Approach
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Mark S. Cracolice, Ed Peters
Chapter16: Solutions
Section: Chapter Questions
Problem 14E
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Using this percent change data, determine the concentration of sucrose that would be isotonic. 

it  does not have to be exact 

Write your answer with 1 digit past the decimal point - e.g. 8.6 (a trailing zero is considered a digit)

 

 

Isotonic concentration =    Moles

 

  • 0.0 M sucrose -0.24×100÷4.6= -5.2%
  • 0.4 M sucrose = 0.39×100/4.2=9.3%
  • 0.6 M sucrose = 0.7×100÷4=17.5% 
  • 0.8 M sucrose =0.8×100/3.7=21.6%
  • 1.0 M sucrose =0.4×100/4.6=8.7%
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