The molar mass of a Volatile Liquid using The Dumas Method Data AnalysisCalculate the molar mass of your unknown for each trial, and report the average. If your instructor provides you withthe accepted molar mass for your unknown, calculate the percent error of your average molar mass.For Your ConsiderationWhy is it not necessary to know the mass of the volatile liquid initially added to the flask?What assumption is being made in determining each of the following?The mass of the vapor.The volume of the vapor.The temperature of the vapor.Thepressureof the vapor.How will the unknown's reported molar mass be affected in each of the following cases?The atmospheric pressure is recorded too high.A small piece of the foil cap was lost before the final mass was meąsured.Condensed water vapor from the bath was trapped underneath the foilcap.The vapor's volume is assumed to be 125 mL (marked on the side of the flask) instead of themeasured volume of the flask.Heating the flask too long resulted in air outside the flask entering and displacing some of thevapor inside the flask.The thermometer is miscalibrated and reads a constant amount too low over its entire temperaturerange. Molar Mass of auolahıle liquid.Tral ĮTemp=374.ISKP=766 mmHgL.0078 atmLatın760 mmtlgV -0.5Ö.00S18md(05.18X10mol)nuuper==30.1 /m5.18 x103molIna2.O TE 374.IS KP=1.007 8 atmV= 0.160L= e0ca O.00525mh(5.25 X0 mol)MM=42.89/moliAug: 36.45 I hnoh88.29/mol88.29/mol36.459/molr 100. arror=/2 eror= 68.7%

Molar Mass Of the volatile liquid is 31.52g/mol.

Answered: Volatile Liquid using The Dumas Method

Science

Chemistry

Volatile Liquid using The Dumas Method

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.24QAP

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Question

The molar mass of a Volatile Liquid using The Dumas Method

Data Analysis
Calculate the molar mass of your unknown for each trial, and report the average. If your instructor provides you with
the accepted molar mass for your unknown, calculate the percent error of your average molar mass.
For Your Consideration
Why is it not necessary to know the mass of the volatile liquid initially added to the flask?
What assumption is being made in determining each of the following?
The mass of the vapor.
The volume of the vapor.
The temperature of the vapor.
The
pressure
of the vapor.
How will the unknown's reported molar mass be affected in each of the following cases?
The atmospheric pressure is recorded too high.
A small piece of the foil cap was lost before the final mass was meąsured.
Condensed water vapor from the bath was trapped underneath the foil
cap.
The vapor's volume is assumed to be 125 mL (marked on the side of the flask) instead of the
measured volume of the flask.
Heating the flask too long resulted in air outside the flask entering and displacing some of the
vapor inside the flask.
The thermometer is miscalibrated and reads a constant amount too low over its entire temperature
range.

Molar Mass of a
uolahıle liquid.
Tral Į
Temp=374.ISK
P=
766 mmHg
L.0078 atm
Latın
760 mmtlg
V -0.5
Ö.00S18md
(05.18X10mol)
nuuper=
=30.1 /m
5.18 x103mol
Ina
2.
O TE 374.IS K
P=1.007 8 atm
V= 0.160L
= e0ca O.00525mh
(5.25 X0 mol)
MM=
42.89/moli
Aug: 36.45 I hnoh
88.29/mol
88.29/mol
36.459/molr 100
. arror=
/2 eror= 68.7%

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