WA Practice 4 - CHEM 1201 Xco Course: 2020 Spring CHEMb My Questions | bartlebyA https://www.webassign.net/web/Student/Assignment-Responses/randomize?pos=9&dep=22671454&tags=autosave#question359932_9...10.0/0 POINTSPREVIOUS ANSWERS2/100 Submissions UsedMY NOTESASK YOUR TEACHERCalculate the pressure of an ideal gas if 0.118 mol of it has a volume of 3.70 L, and a temperature of -11.0 °C. Use R = 0.0821 L-atm/mol-K for the value of the gas constant.O a) The pressure is 1.46 atm.O b) The pressure is 9.39 atm.O c) The pressure is 0.686 atm.O d) The pressure is 0.744 atm.O e) The pressure is 0.0288 atm.11.0/0 POINTSPREVIOUS ANSWERS4/100 Submissions UsedMY NOTESASK YOUR TEACHERCalculate the molar mass of a gas that has a density of 1.23 g/L at 298 °C and 686 torr. Use R = 0.0821 L-atm/mol-K for the value of the gas constant.O a) The molar mass is 2.80 g/mol.O b) The molar mass is 13600 g/mol.O c) The molar mass is 33.3 g/mol.M 2 d) The molar mass is 63.9 g/mol.3:48 AMO Type here to search4/10/2020

According to ideal gas law, where P = pressure = to be calculated (in atm) V = volume of gas = 3.7 L…

Answered: WA Practice 4 - CHEM 1201 X co Course:…

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.17QAP

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Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdk
can you answer, please? the experimental data are Reference: https://www.youtube.com/watch?v=OOXRkycKEOc&feature=youtu.be and https://www.youtube.com/watch?v=3wLJLm0QLpg&feature=youtu.be
Please answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466
There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,k
Please answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466
Ee.5. With explanation please....
Please check my observations from the lab worksheet and watch the video. Accordingly, answer the questions . Link to lab Video: https://drive.google.com/file/d/1BR55ITa7wyOLgLy-MT6ogeXp-fiyuTHn/view?usp=sharing Link to calculated observations: https://drive.google.com/file/d/1zQ952X4N6hOgoToBF_o0zRARScwe54WH/view?usp=sharing Questions:

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