Experimental Value = 40.767%Theoretical Value = 39.165% Was your average experimental mass percent of oxygen in potassium chlorate higher or lower than thetheoretical value (circle one)?HigherLowerWhich of the following sources of error could be used to explain this discrepancy (circle one)?A. The potassium chlorate sample was not heated strongly or long enough.B. Some of the potassium chloride product splattered out of the crucible during the heating process.Explain your choice. Your response should include an analysis of the calculations you performed with yourraw data to obtain your experimental % of oxygen. Mass of original KClO3 sample =Mass of KCl residue =Mass of Oxygen released =Mass Percent of Oxygen in KClO3Average Mass Percent Oxygen =Sample 1[Mass of crucible, lid + KCIO3] -[Mass of crucible + lid] =33.745 g - 32.721 g = 1.024 g[Mass of crucible, lid + residueafter 2nd heating] -[Mass of crucible + lid] =33.314 g - 32.721 g = 0.593 gMass of original KCIO3 sample -Mass of KCI residue =1.024 g - 0.593 g = 0.431 g42.090 +39.4442Mass Percent of Oxygen (experim-Mass Percent of Oxygen (experim-ental) = Mass of Oxygen released /ental) = Mass of Oxygen releasedMass of Potassium chlorate used x Mass of Potassium chlorate used x100 = 0.431 g / 1.024 g x 100 = 100 = 0.383 g / 0.971 g x 100 =42.090 %39.444%81.534Sample 2[Mass of crucible, lid + KCIO3] -Mass of crucible + lid] =33.692 g - 32.721 g = 0.971 g2[Mass of crucible, lid + residueafter 2nd heating] -[Mass of crucible + lid] =33.309 g - 32.721 g = 0.588 gMass of original KCIO3 sample -Mass of KCI residue=0.971 g - 0.588 g = 0.383 g= 40.767 %

Answered: Image /qna-images/answer/226842e6-9f4a-4586-bdb0-6644118fcbf1.jpg

Was your average experimental mass percent of oxygen in potassium chlorate higher or lower than the theoretical value (circle one)? Higher Lower Which of the following sources of error could be used to explain this discrepancy (circle one)? A. The potassium chlorate sample was not heated strongly or long enough. B. Some of the potassium chloride product splattered out of the crucible during the heating process. Explain your choice. Your response should include an analysis of the calculations you performed with your raw data to obtain your experimental % of oxygen.

Was your average experimental mass percent of oxygen in potassium chlorate higher or lower than the theoretical value (circle one)? Higher Lower Which of the following sources of error could be used to explain this discrepancy (circle one)? A. The potassium chlorate sample was not heated strongly or long enough. B. Some of the potassium chloride product splattered out of the crucible during the heating process. Explain your choice. Your response should include an analysis of the calculations you performed with your raw data to obtain your experimental % of oxygen.

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL3: Carbon (13c) Nmr Spectroscopy

Section: Chapter Questions

Problem 13CTQ

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