with a theoretical yield of 80% compute for the percent error of the following data Vial weight= 18.3501 vial + fluorescein weight=18.442 resorcinol = 0.1502g Phthalic anhydride= 0.1022g
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with a theoretical yield of 80% compute for the percent error of the following data
Vial weight= 18.3501
vial + fluorescein weight=18.442
resorcinol = 0.1502g
Phthalic anhydride= 0.1022g
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- The answer with a BCA table for both parts would be great, thank in advance for the help. btw, this is a pre test that isn’t gradedMaterials and detailed methods: paragraph or two explain how the experiment was done Raw Data: Weight of paper weighed -1.834 1 gram of Anthracene= +1.007 0.5 grams of maleic Anhydride= +0.506 Heating bath at 140 C 10 ml of o-xylene added to 1 gram of Anthracene= +1.007 0.5 grams of maleic Anhydride= +0.506 Then place on heating bath at 140 C After heating reagents dissolve Then color changed from yellow to white clear Then mix is cooled in ice bath after a solid product is in the liquid solution You place that in vacuum filtration Product is off white crystal Crude product= +1.428 gYou finish doing an experiemnt with Benzoin. These are the results you get:Boiling start point: 137 ceciusBoiling end point: 130 ceciusVile while empty (with cap on): 15.348Vile with crude prod (with cap on: 15.748 Your starting weight: 1.00115.748 - 15.348 = 0.400 / 1.001 = 0.3996 or 39.96% YieldAnswer the following questions with this information:Initial Mass of impure sample:Mass of recrystallized benzoin:Percent reccovery of Benzoin:Melting pot range of purified benzoin:Literature melting point for benzoin:
- [3] Instructions: Read each excerpt from a research paper and identify the dependent, independent, controlled variable (at least 1), experimental group/treatment, and control group. Antibacterial Assay The test solution of each extract was prepared by dissolving 0.1g of the plant extract separately. 1.0cm3 of dimethyl sulphoxide (DMSO) to get a concentration of 100mg/cm3. The antibacterial activity was performed by filter paper disc diffusion technique. Filter paper disc (Whatman No 1.6 mm diameter) were placed in glass Petri dish and sterilized in a hot air oven. Iwu et al 2018b, the media (10g nutrient Agar in 200cm3 distilled water, autoclaved at 115°C for 30 minutes) was cooled to 50°C. The sterile nutrient Agar media were poured into the sterile Petri dish and allowed to solidify. The bacteria were swabbed with a sterile wire loop. Each disc was impregnated with 0.2cm3 of plant extract. Standard antibiotic Ciprofloxacin was used as a control on a disc with DMSO 100 mg/cm3. The…what is the concentration of the unknown sample using serial diluitions: 0.05M 1.7472nm, 0.025M 0.8569nm, 0.0125M 0.4167nm, 0.00625M 0.1958nm the epsilon value is 0.0101 and l is 1 cm6 PLEASE PROVIDE THE INTERPRETATION OF ALL SAMPLES FOR HELPFUL RATINGS. THANK YOU. *INCLUDE ALL YOUR REFERENCES
- Can you please fill the rest of tghe data based on the on inforamtion you have and answer Average percent by mass of acetic acid in vinegar sample (%) ________________ Standard deviation of percent by mass of acetic acid in vinegar sample (%)analyte concentration(C)(mg/ml) injection volume (ul) elution time (time) peak DAD signal(mAU) caffeine 1 1 4.67 302.85 aspartame 5 1 7.53 15.83 benzoic acid 1 1 8.14 89.98 saccharin 1 1 1.91 84.86 mixture(add everything above with 1:1:1:1 ratio) 1 4.47 69.58 How to get the concentration of the mixture in this case?In the interference experiment preformed, sodium ascorbate powder was added to water to prepare the stock concentration of the interfering substance. On the package label, the manufacturer states that every 1 gram (1,000mg) of sodium ascorbate powder contains 120mg of sodium and 880mg of ascorbate (vitamin C). How much sodium ascorbate must be weighed out (in milligrams) and added to 100 mL of water in order to have a final stock concentration of pure ascorbate equal to 250 mg/dL?
- Mass of crude Acetanilide = 0.508 Mass of filter paper = 0.800g Filter paper + pure Acetanilide = 1.153g Mass of pure Acetanilide = ? % recovery = ? Mpt of recrystallized Acetanilide =112 C – 114 C Mpt of crude Acetanilide = 97 C – 110 CUse the equations of the lines plotted in regards to the data pictured to determine Km and Vmax in the absence and presence of the inhibitor. The Km is ____________mM and the apparent Km is ___________mM. The Vmax is ______________M/min and the apparent Vmax is ______________M/min. Therefore, this must be a _________________ inhibitor.Concentration=2.5 X 10^3 μM OD400nm=0.859 1cm cuvette is used what is the extinction coefficient (μM^-1 cm^-1)