We would like to increase the yield strength of the bar through cold work. (a) Using the Copper curve, how much cold work is needed to get a yield strength of 300MPa Yield strength (MPa) 800 700 600 500 400 300 200 100 0 10 20 1040 Steel 30 40 Brass 50 Copper 60 7(
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- A tensile test was performed on a metal specimen having a circular cross section with a diameter of 1 2 inch. The gage length (the length over which the elongation is measured) is 2 inches. For a load 13.5 kips, the elongation was 4.6610 3 inches. If the load is assumed to be within the linear elastic rang: of the material, determine the modulus of elasticity.The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.
- A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/L =1392 kips/in. What is the modulus of elasticity?A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.Please present FBD/s A tensile test is performed on a brass specimen 10mm in diameter using a gage lenght of 50mm. When the tensile load P reaches a valule of 20kN, the distance between the gage marks has increased by 0.122mm. What is the modulus of elasticitiy of the brass?
- Sample: Malleable Steel (AISI 4145) Original Diameter: 6.14mm Gauge Length: 55 mm Final Length: 68.12 mm Final Diameter: 3.54mm Load (kN) Deformation (mm) Stress (MPa) 12.95 Strain (%) 0.3838 0.54 0.7841 0.95 26.48 1.3899 1.63 1.9485 2.07 3.3090 3.10 4.5821 4.22 5.9359 5.03 7.0340 5.51 8.2413 6.22 10.9446 7.22 13.1951 8.18 12.8228 8.77 12.2583 9.11 12.5915 9.61 13.2536 10.33 13.6636 10.71 13.9772 11.35 14.5433 12.63 15.1155 13.88 15.4970 15.10 15.6484 17.09 15.4031 17.79 14.7655 18.73 13.6721 19.28 10.4617 19.88(b) (i) A tensile test specimen made from 0.4% C steel has a circular cross section of diameter d mm and a gauge length of 25 mm. When a load of 4500 N is applied during the test, the gauge length of the specimen extends to 25.02 mm. If the Young's Modulus of the steel is 199 GPa, calculate the diameter of the tensile test specimen used. 41. The following data were obtained during a tension test of an aluminum alloy. The initial diameter of the test specimen was 0.505 in., and the gage length was 2.0 in. Load ( Ib) Elongation (in.) Load ( Ib) Elongation (in.) 14000 0.020 2310 0.0022 14400 0.025 4640 0.0044 14 500 0.060 6950 0.0066 14600 0.080 9290 0.0088 14800 0.100 I1 600 0.0110 14600 0.120 13000 0.01 50 13600 Fracture Plot the stress-strain diagram and determine the following mechanical properties: a. proportional limit þ. modulus of elasticity S. vield stress at 0.2% offset d. ultimate stress e. nominal rupture stress.
- A compound bar is subjected to a compressive force of P=556 kN by means of a rigid endplate at the top. If the length of the bar is 876mm, determine the stress in the alurninum core. Answer in MPa. Round off your final answer to 2 decimal places. 25 mm Brass core E = 105 GPa a = 20.9 x 10-6/°C Aluminum shell E = 70 GPa Q = 23.6 x 10-6/°C 60 mmFor a tensile test it can be shown that the percent cold work (%CW) is related to strain according to the following relationship: %CW = () × 100 E+1 Using this equation, compute the percent cold work experienced by naval brass (for which the stress-strain behavior is shown in the Animated Figure 6.12) when a stress of 400 MPa (58020 psi) is applied. %CWQuestion One (Compulsory) The following results were obtained during a tensile testing of a highiy ductile bronze specimen: Stress 249 (MPa) Strain 0.001 0.024 0.035 0.041 0.049 0.059 0.074 0.14 498 746 870 995 1119 1244 1368 1493 1552 1552 14 0.43 0.63 0.8 0.9 (B: The original diameter of the test piece was 15 mm and the gauge length was 75 mm. The diameter a fracture was 12.5 mm. Using the graph paper provided, carry out the following: i. Plot the engineering stress - strain diagram ii. Determine the maximum stress on the specimen ii. Calculate the force at ultimate tensile strength point iv. Determine the yield strength Calculate the % elongation V. vi. Calculate the true stress and true strain at fracture point.