Weight of filter paper = 0.756 g Weight of filter paper + barium sulphate precipitate = 0.990 g Weight of barium sulphate precipitate W2 W1 =0.990-0.756 = 0.234 g %3D % Amount of barium in given solution = Ba BasO4 137.36 g 233.36 g 0.234 g 137.36 x 0.234 0.138 g 233.36 Mass of barium X-0.138 g So, Amount of barium in given solution = 0.138 g

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