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- 15.4a 3 please. 0.166 was incorrect.How do you convert 18.8 CP2/TM3 to YY2/ZW3? Use the folowing inequalities: 1CP=2.104 BX, *Bx=4 YY, 1TM=7.1088DD, 1DD=4.966ZW. When writing out the answer leave out the units.ᴀ ꜱᴛᴇᴇʟ ᴛʀᴀɪɴ ʀᴀɪʟ ɪꜱ 400 ᴍᴇᴛᴇʀꜱ ʟᴏɴɢ, ɪɴ ᴍᴀʀᴄʜ ɪᴛ ɪꜱ -30 ᴅᴇɢʀᴇᴇ ᴄ ᴀɴᴅ 40 ᴅᴇɢʀᴇᴇ ᴄ ɪɴ ᴊᴜʟʏ. ᴡʜᴀᴛ ɪꜱ ᴛʜᴇ ᴄʜᴀɴɢᴇ ɪɴ ʟᴇɴɢᴛʜ ɪɴ ᴍᴍ? ᴋ ꜰᴏʀ ꜱᴛᴇᴇʟ = 11.7 x 10^-6 ᴍ/ᴍ-ᴄ
- 2 CoCl2(aq) + 8 NH3(aq) + H2O2(aq) + 2 NH4Cl(aq) 2 [Co(NH3)5Cl]Cl2(s) + 2 H2O(l) In a 50-mL Erlenmeyer flask, cobalt(II) chloride hexahydrate (1.075 g), an aqueous solution of ammonia (1.2 mL, 15 M), ammonium chloride (0.505 g), and hydrogen peroxide (1.0 mL, 30.0% (w/w), density = 1.10 g/mL) were combined. After completion of the reaction, [Co(NH3)5Cl]Cl2 (0.450 g) was isolated. What was the percent yield of the product?a Table: (This is an example of what your data table should look like.) Pressure (kPa) Temperature (°C) Temperature (K) Constant, k(P / T or P•T) Ice water bath 91.58 2.4 275.55 Room temperature 96.54 21.1 294.25 Warm water 104.11 44.5 317.65 Boiling water 113.75 77.5 350.5 Calculations: One way to determine if a relationship is inverse or direct is to find a proportionality constant, k, from the data. If this relationship is direct, k = P/T. If it is inverse, k = P•T. Choose one of these formulas and calculate k for the pairs in your data table (divide or multiply the P and T values). Record the answers in the fourth column of the Data table. How constant were the values for k you obtained in Question 4? Good data may show some minor variation, but the values for k should be relatively constant. Comment on your calculated k values. Analysis Questions: What does temperature measure? Look at your graph. What type…a) 0.498 V b) - 0.498 c) 0.631 d) -00.631 d) none of the above (specify)
- A. B. and C. already solved (https://www.bartleby.com/questions-and-answers/chemistry-question/a89691d6-2162-4677-b0cc-dc84fcceda08). Please answer E, F and GCircle in pencil in the image on th eirght cide of the diagram is a "2"( Pb(NO3)2 ).using exactly 5.00 mL of 0.0400 M stock CuSO4 solution. Add 100 mL of water. Data for Part IMass of empty dish: 32.470 g empty dishVolume of 0.0400 M solution: 5.00 mL CuSO4 solution.Mass of dish and 0.0400 M solution: 37.497 g dish and solutionMass of dish and CuSO4 solid: 32.503 g dish and CuSO4 solidCalculations for Part I1. Calculate the mass of solution2. Calculate the mass of solid CuSO4 dissolved in the solution.3. Calculate the number of moles of solid CuSO4 dissolved in the solution.4. Calculate the mass of water evaporated from the solution.5. Calculate the density of solution, (g solution/mL solution).6. Calculate the % by mass, CuSO4 in solution (100 x g CuSO4/g solution).7. Calculate the molality of solution (moles CuSO4/kg solvent).8. Calculate the molarity of solution (moles CuSO4/L solution).9. Given that the true molarity is 0.0400 M, calculate the percent error of your result.-If ethanol (S.G. = 0.790) were used rather than water in measuring the density of the irregular objects, how would that have affected the result? Explain. -When you were measuring the volume of the irregular solid you were told to stir to eliminate bubbles. If the bubbles were not eliminated, how would that affect the density? Explain. -Suppose the density of 65.0 mL of some liquid was found to be 0.748 g/mL. What would be the specific gravity of 45.0 mL of this liquid?
- How can I convert 728.75468cm/s2 to N/kg ????For the answer choose between A. 0.464 V B. 0.523 V C. 0.818 V D. 0.111 VThe percentage of an additive in gasoline was measured six times with the following results: 0.13; 0.12; 0.16; 0.17; 0.20 and 0.11%. What is the 99% confidence interval for the additive percentage?