What is AG° (in kJ/mol) for the autoionization of water at 25°C?R = 8.314462 J/K-molIMPORTANT: When entering your answer:• Enter the number only (no units)• Do not leave any spaces• Include the sign if your answer is negative (not necessary forpositive values)• Use a leading zero before the decimal when necessaryReport your number to 1 decimal place (regardless of thesignificant figures)• Correctly round your answer to the 1st decimal place (marginof allowed error is only ± 0.1, so always use un-roundednumbers in your calculations). If the last digits are zeros theywill not display once you click away, but the answer will stillbe marked correct.Examples: 12.3 or -0.4

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Answered: What is AG° (in kJ/mol) for the…

What is AG° (in kJ/mol) for the autoionization of water at 25°C? R = 8.314462 J/K•mol IMPORTANT: When entering your answer:

Pushing Electrons

4th Edition

ISBN:9781133951889

Author:Weeks, Daniel P.

Publisher:Weeks, Daniel P.

Chapter3: Mechanisms

Section: Chapter Questions

Problem 31EQ: The reaction just described is reversible. Deprotonation of the conjugate acid of an organic base by...

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Question

What is AG° (in kJ/mol) for the autoionization of water at 25°C?
R = 8.314462 J/K-mol
IMPORTANT: When entering your answer:
• Enter the number only (no units)
• Do not leave any spaces
• Include the sign if your answer is negative (not necessary for
positive values)
• Use a leading zero before the decimal when necessary
Report your number to 1 decimal place (regardless of the
significant figures)
• Correctly round your answer to the 1st decimal place (margin
of allowed error is only ± 0.1, so always use un-rounded
numbers in your calculations). If the last digits are zeros they
will not display once you click away, but the answer will still
be marked correct.
Examples: 12.3 or -0.4

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