What is output? new_list - [['abc', 'def'], 10, 20] print(new_list[0])
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- q6) Which of the following linked list can move only in one direction to access the data of the node? a. Single linked list b. Circular Double linked list c. None d. Double linked listThis code by C to : 1- Create a sorted linked list using tenStudent array (copy from array into the linked list will be done). 2-Append an element to the end of a list and Details in the picture: >>>>>>>>>>>>>>>>>>>>>>> I want to update the code to : 1- Delete the last element from a list. 2- Delete the nth element from a list. The code: #include<stdio.h> struct student{int TC;char F_name[12];char L_name[12];int age;char gender[2];}; struct Linked_list_node{struct student info;struct node* next;}; struct student tenStudent[10] = {123,"X1","Y1",21,"M",234,"X2","Y2",26,"F",128,"X3","Y3",18,"M",432,"X4","Y4",27,"M",287,"X5","Y5",34,"F",423,"X6","Y6",21,"M",634,"X7","Y7",16,"F",828,"X8","Y8",15,"M",252,"X9","Y9",27,"F",887,"X10","Y10",34,"F",}; int main(){//create a head node for linked liststruct Linked_list_node* head = (struct Linked_list_node*)malloc(sizeof(struct Linked_list_node));//add first student to the…C++ What is the output of following function for start pointing to first node of following linked list? 1->2->3->4->5->6 void fun(Node<ItemType>* start) { if(start == nullptr) return; cout << start->getItem() << " "; if(start->getNext() != nullptr ) fun(start->getNext()->getNext()); cout << start->getItem() << " ";} eof.
- Which of the following statements are true? A. Appending of elements to a dynamic list takes constant time. B. Row-wise traversal of 2-dimensional arrays is commonly faster than column-wise traversal. C. Tranversing an array is faster than traversing a linked list with the same number of entries. D. Node lookup time in a balanced binary search tres is O(1).C++ ONLY Add the following functions to the linked list. int getSize() -> This function will return the number of elements in the linked-list. This function should work in O(1). For this keep track of a size variable and update it when we insert a new value in the linked-list. int getValue(index) -> This function will return the value present in the input index. If the index is greater or equal to the size of the linked-list return -1. void printReverse() -> This function will print the linked list in reverse order. You don’t need to reverse the linked list. Just need to print it in reverse order. You need to do this recursively. You cannot just take the elements in an array or vector and then print them in reverse order. void swapFirst() -> This function will swap the first two nodes in the linked list. If the linked-list contains less than 2 elements then just do nothing and return. To check your code add the following code in your main function. LinkedList l;…(c++)write a program to insert node at specified number in single linked list? (c++)write a program to insert node at specified number in double linked list?
- When a list is implemented using an array, which of the following is FALSE? Select one: A.If the size of the array is insufficient, it whole list will be automatically copied to a new array B.The new node inserted might cause shifting of the existing elements C.The insertion of a new element is proportional to the size of the list D.The memory allocation can be very inefficientq9) In which of the following linked list there will be no beginning and ending? a. Depends on the Problem. b. Single Linked List. c. Double Linked List. d. Circular Linked List.When a list is implemented using an array, which of the following is FALSE? Select one: A.If the size of the array is insufficient, there is a need to copy the whole list to a new array B.The new node inserted might cause shifting of the existing elements C.The memory allocation can be very inefficient D.The insertion of a new element is proportional to the size of the list
- # Create a list of tuplestuples = [("p", 1), ("q", 2), ("r", 3)]# Use enumerate() to iterate over the tuples and print the index and valuefor index, value in enumerate(tuples):print(index, value)This code will print the following output:0 p1 q2 r Could you try to modify your code to get the output mentioned by you? Also, the output for the above function should be0 ('p', 1)1 ('q', 2)2 ('r', 3) Could you please confirm?I'm trying to delete a node after inputting data for 2-3 checks but the node I try to delete remains in the list. How do I fix my deleteCheck() function to run correctly with the rest of my code? Thank you. #include <stdio.h>#include <stdlib.h>// Austin Chong// The core concept of this assignment is to use a linked list in a C program.// 07 March 2020 struct checkNode{int checkNumber;char date[8];char paidTo[100];char description[100];double amount;struct checkNode *head;struct checkNode *next;}; struct checkNode *checkBook = NULL; /* Functions */ void addCheck(){int checkNumber;double amount;char temp;struct checkNode *newCheck = (struct checkNode*) malloc(sizeof(struct checkNode));printf("Please enter the check number: ");scanf("%d", &checkNumber);newCheck -> checkNumber = checkNumber;printf("Please enter the amount: ");scanf("%lf", &amount);newCheck -> amount = amount;printf("Please enter the date: ");scanf("%c", &temp);scanf("%[^\n]", newCheck ->…Q4 Suppose, alist is a 2-dimensional list that is defined as follows. alist = [ [1], [2,3], [5,6,7] ] Which is the best option to access the last element of the last element of this list (i.e., 7)? Question 4 options: alist[ len(alist) - 1 ][len(alist[len(alist) - 1]) - 1] alist[ len(alist) - 1 ][len(alist[len(alist) - 1])] alist[3][3] alist[ len(alist) - 1 ][1]