What is the depth factor in Taylor's stability analysis if the depth of hard stratum below toe is 5m and height of slope above toe is 10 m?
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- GEOTECHNICAL ENGINEERINGFor the clay slope, on rock determine the FS. If Kh = 0.4 (seismic factor)data H = 16 m β = 30 ° Ysat = 20 kn / m3 Cu = 50 kn / m2Research about the background study of DIRECT SHEAR TEST FOR SOIL and discuss.What is the shearing strength of soil in kPa along a horizontal plane at a depth of 4 m in a deposit of sand having the following properties: Angle of internal friction, ∅ = 35°; Dry unit weight, yd = 17 kN/m3 ; Specific gravity, Gs = 2.7; Assume the ground water table is at a depth of 2.5 m from the ground surface a.11 b.95 c.23 d.41
- A cut slope of h= 7m was excavated in a saturated clay with a slope of angle beta = 45 degrees with the horizontal. The Previous explorations showed that a rock layer was located at a depth of 14 m. Given that, c = 60 kN/m² and unit weight = 17 kN / (m ^ 3) . Determine the factor of safety.A soil along a horizontal plane at a depth of 4 m in a deposit of sand having the following properties: Angle of internal friction, ∅ = 35° ; Dry unit weight, yd = 17 kN/m3 ; Specific gravity, Gs =2.7. Assume the ground water table is at a depth of 2.5 m from the ground surface. Find the change in shear strength in kPa when the water table rises to the ground surface. a. 11 b. 95 c. 23 d. 41(Note:Depth of rock layer is 2m not 12 m.) Q A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 21 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?
- REMIDAL MEASURES FOR SLOPE STABILITYA cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following. a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?Q.3. A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 19 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?
- Given data: Depth of Clay layer =4Depth of Sand layer=2unit weight of clay kN/m3=23unit weight of sand kN/m3 =21Ø in both layers=30C´= 01. A vertical cut is made through a homogeneous soil mass (c=20 kPa,ϕ=20°,γ=16.50 ?? ?3 ⁄ ). Estimate thesafe depth of the cut, taking a factor of safety of 2 using Culmann’s methodA soil profile is shown in Figure ?-?. Compute the shear strength on the horizontal and vertical planes at points ? and ?.