Asked May 6, 2019

What is the energy released in this nuclear reaction 199F+42He→2210Ne+11H919F+24He→1022Ne+11H? (The atomic mass of 19F19F is 18.998403 u, and that of 22Ne22Ne is 21.991385 u)


Expert Answer

Step 1

The expression for the nuclear reaction is,

Step 2

The expression for the energy released is,

Step 3

Substitute the ...


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