What is the output of the following C program? #include int main (int argv, char* argc[]) { int x = 280; char* ptr_p = printf("%d\n", * ptr_p); return 0; (char*) &x; }
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- Please read the question to the very end. Below is an example of a code that we need to reprogram in C++ #include <iostream>const char* filename = "Humans.dat";struct Human {char name[20];int phone;};void my_scanf(Human *s, unsigned short int n) {printf("Enter name %hu >", n+1); scanf("%25s", s->name);printf("Enter phone >"); scanf("%i", &s->phone);}void my_printf(Human *s, unsigned short int n) {for (unsigned short int i = 0; i < n; i++)printf("%i. Name: %s, phone: %i\n", i+1, s[i].name, s[i].phone);}void read_from_user_and_save_to_file() {unsigned short int m; printf("Enter count of Humans >"); scanf("%hu", &m);Human* AllHumans = new Human[m];for (unsigned short int i = 0; i < m; i++) my_scanf(&AllHumans[i], i);my_printf(AllHumans, m);FILE * fp = fopen(filename, "wb");fwrite(AllHumans, sizeof(Human), m, fp); fclose(fp);}void read_from_file_and_show_to_user() {FILE * fp = fopen(filename, "rb");fseek(fp, 0, SEEK_END);unsigned int fsize =…What does the following C++ program print? Why? #include <iostream> using namespace std; int a=480, b=380, c=42; void f(int x, int &y, int *z) { ++x; ++y; ++*z; } int main() { cout <<"a="<<a <<" b="<<b <<" c="<<c <<endl; f(a,b,&c); cout <<"a="<<a <<" b="<<b <<" c="<<c <<endl; }When a variable is stored in memory, it is associated with an address. To obtain the address of avariable, the & operator can be used. For example, &a gets the memory address of variable a.Let's try some examples.Write a C program addressOfScalar.c by inserting the code below in the main function. 1 // intialize a char variable, print its address and the next address2 char charvar = 'a';3 printf("address of charvar = %p\n", (void *)(&charvar));4 printf("address of charvar - 1 = %p\n", (void *)(&charvar - 1));5 printf("address of charvar + 1 = %p\n", (void *)(&charvar + 1));67 // intialize an int variable, print its address and the next address8 double doublevar = 1.0;9 printf("address of doublevar = %p\n", (void *)(&doublevar));10 printf("address of doublevar - 1 = %p\n", (void *)(&doublevar - 1));11 printf("address of doublevar + 1 = %p\n", (void *)(&doublevar + 1)); Questions:1) Run the C program, attach a screenshot of the output in the answer…
- I need complete explanation of c++ code line by line. Need Explanation of all lines of code what is happening in this code where the data is stored.? Code #include <iostream>#include <iomanip>#include <time.h>#include <fstream>#include <conio.h>#include <string.h>#include <stdlib.h>using namespace std;class Bank {public:};class ATMAccountHolders:public Bank{string accountHolders;string accountHoldersAddress, branch;int accountNumber;double startBalance;double accountBalance; double amount;int count;public:void deposit();void withdraw();void accountExit();ATMAccountHolders(){accountNumber = 7787;accountHolders = " Ammad Naseer";accountHoldersAddress = " House no.112";startBalance = 6000.00;accountBalance = 6000.00;branch = " Islamabad";amount = 20000; }}; void ATMAccountHolders::deposit(){system("cls"); cout<<" ATM ACCOUNT DEPOSIT SYSTEM ";cout<<"\n\nThe Names of the Account Holders are…- c program only Hi! Could you help me? I think something is wrong with my code but I couldn't figure out what. Also, please help me fix the `factorial` function, for it should apply recursion. Thanks! #include<stdio.h> int factorial(int n); int main(void) { int n; printf("Enter n: "); scanf("%d", &n); printf("Factorial of %d is %d", n, factorial(n)); return 0;} int factorial(int n) { if(n <= 1) { return 0; }else{ return factorial(n-1)*n; }} You can see below the attached pic of how the output should beWhat happens if the statement free(a) is removed in the following C code? int *a; a=(int*)malloc(sizeof(int)); *a=100; printf("*a%d",*a); free(a); Question 4 options: Error Memory Leak Dangling Pointers Segmentation Fault
- 1. Compile and run the following C++ program: #include <iostream> #include <cstdlib> using std::cout; using std::endl; int main() { int integer1, * p1, ** p2; integer1 = 10; // line 11 p1 = &integer1; // line 12 p2 = &p1; // line 13 cout << "integer1 = " << integer1 <<endl; // line 15 cout << "p1 = " << p1 << endl; // line 16 cout << "p2 = " << p2 << endl; // line 17 return EXIT_SUCCESS; } // main 2. Suppose after the declaration of variables integer1, p1, and p2, we have the following memory map: Symbol Name | Type | Memory Address integer1 | int | 80 p1 | int * | 84 p2 | int ** | 92 (a) Fill in the “Value” column in the in the memory map to reflect the changes that are caused by lines 11, 12, and 13. (b) If we substitute lines 15–17 with the the following two statements, then what will be the output of the program? (*p1)++; cout << "integer1 = " << *p1 << endl; (c) Will the output of the…Please written by computer source The code needs to be tested on a raspberry pi zero Write a program in C that, when ran, asks the user for two values whose difference cannot exceed 12 - if it does, give a warning and request the yalue again. It will then compute the (recursive) factorial of that difference and print the result to the screen. - The C program must have a prompt that requests two values as input from the user and only exits on explicit user command - The C program must find the difference of the user values in an assembly.S file (capital S) - The C program must call the factorial function from an assembly.S file (capital S) In your README, answer why the difference of the two values must be less than 13.The topic is Booth's algorithm - Explain this C programming code - i have a seminar. //header files #include #include #include int a=0,b=0,c=0,a1=0,b1=0,com[5]={1,0,0,0,0}; int anum[5]={0},anumcp[5] ={0},bnum[5]={0}; int acomp[5]={0},bcomp[5]={0},pro[5]={0},res[5]={0}; // binary function void binary(){ a1 = fabs(a); b1 = fabs(b); int r, r2, i, temp; //for loop for binary for(i = 0; i < 5; i++){ r = a1 % 2; a1 = a1 / 2; r2 = b1 % 2; b1 = b1 / 2; anum[i] = r; anumcp[i] = r; bnum[i] = r2; if(r2 == 0){ bcomp[i] = 1; } if(r == 0){ acomp[i] =1; } } //2's complimanting part for the program c = 0; for( i = 0; i < 5; i++){ res[i] = com[i]+ bcomp[i] + c; if(res[i]>=2){ c = 1; } else c = 0; res[i] =…
- What is the value of the variable sum once the following C code has been executed? #define N = 5int a[] = {1,2,3,4,5}p = &a[0]; while (p < &a[N]) sum += *(p++);What will be the output of the following program in C ? #include<stdio.h> int main(int argc, char const *argv[]) { printf("%d\n", (int)sizeof('a')); return 0; }N real numbers entered by the user on the keyboard are in order from the smallest to the largest. Write a C program that checks that it is not. In your program, you are checks for correct sequencing, returning to 1 for ordered arrays, 0 for unordered arrays, and You need to write a function compatible with the prototype given below. Function recursive must be and do not use a loop within the function. int IsSorted(double x[], int N){}