What is the potential, E , for this cell?Are reactants or products favored in this reaction? Consider the following reaction:2Cr**(aq) + 6Fe*+*(aq)+ 7H2O(1) = Cr2O,2(aq) + 6FE²*(aq) + 14H*(aq)

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What is the potential, E , for this cell?

Are reactants or products favored in this reaction?

Consider the following reaction:
2Cr**(aq) + 6Fe*+*(aq)+ 7H2O(1) = Cr2O,2(aq) + 6FE²*(aq) + 14H*(aq)

Expert Solution

Step 1

In an electrochemical cell, there are two half cells namely, reduction half-cell and oxidation half-cell. If a species loses one or more electrons, then it is an oxidation reaction. If a species gains an electron or more, then it is a reduction reaction. In electrochemical cell, oxidation takes place at anode whereas reduction takes place at cathode.

The given reaction is,

$2 {Cr}^{3 +} + 6 {Fe}^{3 +} + 7 H_{2} O \overset{}{\to} {Cr}_{2} O_{7}^{2 -} + 6 {Fe}^{2 +} + 14 H^{+}$

The half-cell reactions are,

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