What volume (in mL) of 0.250 M HCI would be required to completely react with 4.00 g of Al in the following chemical reaction? 2 Al(s) + 6 HCI(aq) → 2 AICI3 (aq) + 3 H2(g) mL 1 2 4 6 C 7 8 9 3.
What volume (in mL) of 0.250 M HCI would be required to completely react with 4.00 g of Al in the following chemical reaction? 2 Al(s) + 6 HCI(aq) → 2 AICI3 (aq) + 3 H2(g) mL 1 2 4 6 C 7 8 9 3.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 91QRT
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Step 1
Given mass of aluminum = 4 g
Molar mass of aluminum = 27 g/mol
Number of moles of aluminum is determined by dividing the given mass of aluminum by its molar mass.
Number of moles of aluminum = 4/27 = 0.148 mol
Number of moles of hydrochloric acid that reacts with 2 mol of aluminum = 6 mol
Number of moles of hydrochloric acid that reacts with 1 mol of aluminum = 3 mol
Number of moles of hydrochloric acid that reacts with 0.148 mol of aluminum = 0.148 × 3 = 0.444 mol.
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