What volume of 1.73 M K2Cr2O7 is required to titrate 1.85 g of CH3OH dissolved in 30.0 mL of solution?

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Problem 60QAP: 60. Suppose 325 in L of 0.150 M NaOH is needed for your experiment. How would you prepare this if...
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What volume of 1.73 M K2Cr2O7 is required to titrate 1.85 g of CH3OH dissolved in 30.0 mL of solution?
Expert Solution
Step 1

Given:

Mass of CH3OH=1.85 g

The molar mass of CH3OH=32.04 g/mol

Moles=Given mass/ Molar mass

Moles=(1.85 g)/(32.04 g/mol)

Moles=0.05774 mol

 

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