What volume of water vapor in liters could be generated at 0.986 atm and 435. K by the combustion of 270.08 grams of pentane (C5H12) with excess oxygen gas? C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g) R = 0.08206 L atm/ mol K

Chemistry for Engineering Students
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Chapter5: Gases
Section: Chapter Questions
Problem 5.51PAE: 51 What volume of oxygen at 24 C and 0.88 atm is needed to completely react via combustion with 45 g...
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What volume of water vapor in liters could be generated at 0.986 atm and 435. K by the combustion of 270.08 grams of pentane (C5H12) with excess oxygen gas?

C5H12(g) + 8 O2(g) ---> 5 CO2(g) + 6 H2O(g)

R = 0.08206 L atm/ mol K

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