What would be the contents of q1 after applying the following operations? ArrayQueue q1= new ArrayQueue(5); for(int i = 1, i< 5; i++) q1.offer(i ); while( q1.peek() == 1) q1.poll(); front → rear 1 2 3 4 front → rear 3 4 front → rear 3 4 q1 will be empty
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What would be the contents of q1 after applying the following operations?
ArrayQueue<Integer> q1= new ArrayQueue<Integer>(5);
for(int i = 1, i < 5; i++)
q1.offer(i );
while( q1.peek() == 1)
q1.poll();
-
front → rear
1 2 3 4
-
front → rear
3 4
-
front → rear
2 3 4
-
q1 will be empty
-
Step by step
Solved in 2 steps
- How to complete the following code, and then use the program showed in screenshot to test it. I have also attach screenshot of the StackInterface code public class ArrayStack<T> implements StackInterface<T> {public static int CAPACITY = 100;private final T[] elements;private int topIndex; public ArrayStack() {} public ArrayStack(int size) {// Initialize size of elements// Initialize topIndex to -1} public void push(T obj) {} public T top() {} public void pop() {} public boolean isEmpty() {} public boolean isFull() {}public int getStackSize() {// Return stack size, i.e., number of elements} @Overridepublic String toString() {String s = "The stack is: "; for (int i = topIndex; i >= 0; i--)s += elements[i] + " "; return s;}}In JAVA, use a HashMap to count and store the frequency counts for all the words from a large text document. Using file util, please. Then, display the contents of this HashMap with words and frequency count. Next, please create a set view of the Map and store the contents in an array. Sort this array based on key value and display it. Finally, sort the array in decreasing order by frequency and display it as well. Please label your explanation in the code Thank youImplement keys() for SeparateChainingHashST and LinearProbingHashST. 0 Add a method to LinearProbingHashST that computes the average cost of a search hit in the table, assuming that each key in the table is equally likely to be sought.
- In Java, if we say int[] myArray = new int[10];, then myArray has 10 entries with indices 0,1,2,3,4,5,6,7,8, and 9. True FalseGiven an empty ArrayList<Integer> numList, what are numList's contents after the following operations: numList.add(12);numList.add(14);numList.add(16);numList.set(1, 13);numList.add(0, 10); Group of answer choices a) 10, 12, 13, 16 b) 10, 12, 13, 14, 16 c) 10, 13, 14, 16 d) 10, 16, 13, 12In JAVA, use a HashMap to count and store the frequency counts for all the words from a large text document. Then, display the contents of this HashMap with given words and their frequency in the document. Next, please create a set view of the Map and store the contents in an array. Sort this array based on key value and display it. Finally, sort the array in decreasing order by frequency and display it.
- Need help with the parts that say TODO in images , This may be needed scoresheet code below package edu.vtc.cis2271.yahtzee; import java.util.ArrayList;import java.util.HashSet;import java.util.List;import java.util.Set; public class Scoresheet{ private static final int SMALL_STRAIGHT_SCORE = 30;private static final int LARGE_STRAIGHT_SCORE = 40;private static final int FULL_HOUSE_SCORE = 25;private static final int YAHTZEE_SCORE = 50;private static final int TOP_HALF_BONUS = 35;private static final int TOP_HALF_BONUS_LEVEL = 63; @SuppressWarnings("javadoc")public enum Category {Ones,Twos,Threes,Fours,Fives,Sixes,SmallStraight,LargeStraight,ThreeOfKind,FourOfKind, FullHouse, Yahtzee,Chance} public Scoresheet(){_scores = new int[Category.values().length];_listeners = new ArrayList<>();for (int i = 0; i < _scores.length; i++)_scores[i] = -1;} public void addScoreSheetListener(ScoreSheetListener listener){_listeners.add(listener);} public void…// Only few methods are mentioned here //Do remaining methods to pass the test methods /*** Removes the specified (num) of the given element from the internal ArrayList of elements. * If num <= 0, don't remove anything. * If num is too large, remove all instances of the given element from the internal ArrayList of elements.* Example:* - For a defined CustomIntegerArrayList containing the integers: 1, 2, 1, 2, 1* - Calling remove(2, 1) would remove the first 2 instances of 1 * - The CustomIntegerArrayList will then contain the integers: 2, 2, 1* - For a defined CustomIntegerArrayList containing the integers: 100, 100, 100 * - Calling remove(4, 100) would remove all instances of 100 * - The CustomIntegerArrayList will then be empty* - For a defined CustomIntegerArrayList containing the integers: 5, 5, 5, 5, 5 * - Calling remove(0, 5) would remove nothing* * @param num number of instances of element to remove * @param element to remove*/ public void remove(int num, int element) {//…Given an ArrayList of Integers, find a subarray with the maximum sum of any potential subarray within the ArrayList. A subarray is any combination of consecutive numbers. The subarray can be of any length n, where the size of n >= 0. import java.util.ArrayList;public class MaxSubArray{public static ArrayList<Integer> solution(ArrayList<Integer> nums){// ↓↓↓↓ your code goes here ↓↓↓↓return new ArrayList<>();}}
- Is there a particular reason why I do not get the right answer after I choose my option? Entering student ID ( that was previously entered ) and then displayed something different? This is the code : import java.util.ArrayList;import java.util.Iterator;import java.util.Scanner;class UniversityPersonnelManagement {public static void main(String[] args) {ArrayList<Student> studentList= new ArrayList<Student>();ArrayList<Faculty> facultyList= new ArrayList<Faculty>();System.out.println("Welcome to my Personal Management Program");for(;;){int input=0;System.out.println(" Choose one of the options:");System.out.println("1- Add a new Faculty member");System.out.println("2- Add a new Student");System.out.println("3- Print tuition invoice for a student");System.out.println("4- Print information of a faculty");System.out.println("5- Exit Program");System.out.print(" Enter your selection: ");Scanner s=new Scanner(System.in);try{input=s.nextInt();}catch (Exception e)…Add a constructor to SeparateChainingHashST that gives the client the abilityto specify the average number of probes to be tolerated for searches. Use array resizingto keep the average list size less than the specified value, and use the technique describedon page 478 to ensure that the modulus for hash() is primeHELP WITH EXAMPLES OF THE METHODS, IN THE TODO package integerarraylist; import static org.junit.jupiter.api.Assertions.*; import java.util.ArrayList; import org.junit.jupiter.api.Test; class CustomIntegerArrayListTest { @Test void testGetArrayList() { //create a new empty CustomIntegerArrayList CustomIntegerArrayList arr1 = new CustomIntegerArrayList(); arr1.add(2); arr1.add(0, 5); arr1.add(1, 5); ArrayList<Integer> lst1 = new ArrayList<Integer>(); lst1.add(2); lst1.add(0, 5); lst1.add(1, 5); assertEquals(lst1, arr1.getArrayList()); ArrayList<Integer> arr4Elements = new ArrayList<Integer>(); arr4Elements.add(100); arr4Elements.add(200); arr4Elements.add(500); //create a new CustomIntegerArrayList with the elements in the given ArrayList CustomIntegerArrayList arr4 = new CustomIntegerArrayList(arr4Elements); ArrayList<Integer> lst4 = new ArrayList<Integer>(); lst4.add(100); lst4.add(200); lst4.add(500); assertEquals(lst4,…