What would the concentration of CH3C00 be at pH 5.3 if 0.1M CH3CO0H was adjusted to that pH. 1) pH = pK + Log [A ] %3D [HA] 2) CH3C00H CH3C00 + H 3) Find equilibrium value of [A ]i.e [CH3C00 ] 4) pH = 5.3; pK = 4.76 5) Let X = amount of CH3C00H dissociated at equilibrium (A ] = [X] [HA] = [0.1 - X] 6) 5.3 = 4.76 + Log IXI [0.1- X]
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What would the concentration of CH3COO be at pH 5.3 if 0.1M CH3COOH was adjusted to that pH.
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