When a mass of 2 kilograms is attached to a spring whose constant is 32 N/m, it comes to rest in the equilibrium position. Starting at t = 0, a force equal to f(t) = 102e2" cos(4t) is applied to the system. Find the equation of motion in the absence of damping. -o여(41) + 을해in(41) + e" x(t) = x m

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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When a mass of 2 kilograms is attached to a spring whose constant is 32 N/m, it comes to rest in the equilibrium position. Starting at t = 0,
a force equal to f(t)
= 102e-2t
cos(4t) is applied to the system. Find the equation of motion in the absence of damping.
cos(4) + Zsin(4) + e-"( co(4) – sin(41)
x(t) =
Transcribed Image Text:When a mass of 2 kilograms is attached to a spring whose constant is 32 N/m, it comes to rest in the equilibrium position. Starting at t = 0, a force equal to f(t) = 102e-2t cos(4t) is applied to the system. Find the equation of motion in the absence of damping. cos(4) + Zsin(4) + e-"( co(4) – sin(41) x(t) =
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