Which of the following best explains why the synthetic route shown below would be unsuccessful? 1) CH;CH,Br HCEC: CH;CH,C=CC(CH3)a 2) NANH2 3) (CH3)3CBr O Reaction with sodium amide will result in formation of a primary alkyne O The alkynide anion formed by reaction with sodium amide will facilitate an E2 (rather than SN2) reaction with t-butyl bromide O The alkynide anion is not a strong enough nucleophile to react with 1-bromopropane in step 1 Sodium amide is not a strong enough base to deprotonate the terminal alkyne in step 2 O Both substitution reactions will occur on the same end of the alkyne, making a product different than the one shown

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter11: Ethers, Epoxides, And Sulfides
Section11.9: Reactions Of Epoxides
Problem DQ
icon
Related questions
Question
Which of the following best explains why the synthetic route shown below would be
unsuccessful?
1) CH;CH2Br
HCEC:
CH3CH2C=CC(CH3)3
2) NaNH2
3) (CH3)3CBR
O Reaction with sodium amide will result in formation of a primary alkyne
O The alkynide anion formed by reaction with sodium amide will facilitate an E2 (rather than SN2) reaction
with t-butyl bromide
O The alkynide anion is not a strong enough nucleophile to react with 1-bromopropane in step 1
O Sodium amide is not a strong enough base to deprotonate the terminal alkyne in step 2
O Both substitution reactions will occur on the same end of the alkyne, making a product different than the
one shown
Transcribed Image Text:Which of the following best explains why the synthetic route shown below would be unsuccessful? 1) CH;CH2Br HCEC: CH3CH2C=CC(CH3)3 2) NaNH2 3) (CH3)3CBR O Reaction with sodium amide will result in formation of a primary alkyne O The alkynide anion formed by reaction with sodium amide will facilitate an E2 (rather than SN2) reaction with t-butyl bromide O The alkynide anion is not a strong enough nucleophile to react with 1-bromopropane in step 1 O Sodium amide is not a strong enough base to deprotonate the terminal alkyne in step 2 O Both substitution reactions will occur on the same end of the alkyne, making a product different than the one shown
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Amines
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9781305580350
Author:
William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:
Cengage Learning
Organic Chemistry: A Guided Inquiry
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:
9780618974122
Author:
Andrei Straumanis
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9781305080485
Author:
John E. McMurry
Publisher:
Cengage Learning